矩阵行的平方和

Question

任务是在不使用数组的情况下输出每一行的平方和之和。我已经编写了一个代码并且它完成了工作，只是我找不到一种方法可以根据第一个输入动态调整矩阵的大小，这将是矩阵的大小，而不是按 'enter'在每个元素之后，用户可以用 'space' 分隔每个元素并用 'enter' 分隔行，就像在实际矩阵中一样。如果有办法，请告诉我。这是需要在每个元素后按 'enter' 的代码。

/*Take matrix size as input. read each element and give out the sum of squaresum of rows of the matrix*/
#include <stdio.h>
int main(){
    int m,n;    //matrix size row,column
    int rowsum = 0,sum = 0,a,col,row = 0;
    printf("Enter the size of matrix\n");
    scanf("%d %d",&m,&n);   //take row and col
    while (row!=m)      //calculate sum of each element of column one by one row-wise
    {
        col = 0;    //start from col 1 i.e col 0
        rowsum = 0; 
        printf("Enter elements of %d row\n",row+1);
        while (col!=n){     //calculate sum of each element of rows one by one col-wise
            scanf("%d",&a); //read the element
            rowsum += a;    //add read element to sum of that row
            col ++; //move to next element
        }
        sum += rowsum*rowsum;   //add the sq. of that rowsum before moving on to next
        row ++; //move to next row
    }
    printf("%d is sum of squaresum of rows",sum);
    return 0;
}

提前致谢。

Answer 1

您可以在扫描时去掉下一个字符，这样您就可以在数字后只输入一个 space。此外，您可以通过这种方式在数字之间放置任何字符。使用“%*c”在扫描时跳过一个字符。这是代码：

/*Take matrix size as input. read each element and give out the sum of squaresum of rows of the matrix*/
#include <stdio.h>
int main(){
    ...
    while (row!=m)      //calculate sum of each element of column one by one row-wise
    {
        col = 0;    //start from col 1 i.e col 0
        rowsum = 0;
        printf("Enter elements of %d row\n",row+1);
        while (col!=n){     //calculate sum of each element of rows one by one col-wise
            scanf("%d%*c",&a); //read the element

            rowsum += a;    //add read element to sum of that row
            col ++; //move to next element
        }
    ...
    }
    return 0;
}

当大小选择为 (2, 3) 时，一行的一些可能输入：

Enter the size of matrix
2 3
Enter elements of 1 row
1;2;3
Enter elements of 2 row
4;5;6

输出：

261 is sum of squaresum of rows

另一种可能的方式：

Enter the size of matrix
2 3
Enter elements of 1 row
1 2 3
Enter elements of 2 row
4 5 6

输出同上

矩阵行的平方和

sum of squaresum of rows of the matrix

c

loops

matrix