如何在 Android 中使用 xml 实现此可绘制对象

Question

我可以得到这条线，但它不是弯曲的，使用角半径不适用于下面的

<?xml version = "1.0" encoding = "utf-8"?>
<layer-list xmlns:android = "http://schemas.android.com/apk/res/android">
    <item>
        <shape android:shape = "rectangle">
            <solid android:color = "#F7B500"/>
        </shape>
    </item>
    <item android:left = "4dp">
        <shape android:shape = "rectangle">
            <solid android:color = "#FFF8E7"/>
        </shape>
    </item>
</layer-list>

Answer 1

也许这对你有用：

<?xml version = "1.0" encoding = "utf-8"?>
<layer-list xmlns:android = "http://schemas.android.com/apk/res/android">
    <item>
        <shape android:shape = "rectangle">
            <solid android:color = "#FFF8E7"/>
            <corners android:radius="2dp" />
        </shape>
    </item>
    <item android:gravity="left">
        <shape android:shape = "rectangle">
            <solid android:color = "#F7B500"/>
            <corners android:radius="2dp" />
            <size android:width="4dp" />
        </shape>
    </item>
</layer-list>

Answer 2

也许这对你有用：

<?xml version="1.0" encoding="UTF-8"?>
<layer-list xmlns:android="http://schemas.android.com/apk/res/android">
    <item>
        <shape android:shape="rectangle">
            <padding
                android:bottom="10dp"
                android:left="10dp"
                android:right="10dp"
                android:top="10dp" />
            <corners android:radius="10dp" />
            <solid android:color="#AA00FF" />
        </shape>
    </item>
    <item android:gravity="left">
        <shape android:shape="rectangle">
            <solid android:color="#F7B500" />
            <corners android:radius="2dp" />
            <size android:width="4dp" />
        </shape>
    </item>
</layer-list>

如何在 Android 中使用 xml 实现此可绘制对象

How to achieve this drawable using xml in Android

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android-drawable