运行 x86 汇编中的程序总数
Running total program in x86 assembly
我正在尝试用 x86 汇编编写一个程序，该程序在输入 0 之前采用整数输入，此时它会打印所有输入的整数之和，以及其中的最小值。我以前在 MIPS 汇编中编写过相同的程序，但是 运行 在 x86 版本中出现错误，其中总和似乎没有在 add 命令中递增。我怎样才能让它工作？我应该直接使用寄存器吗？我已经包含了 MIPS 程序和我在 x86 中的尝试，它还没有最小值部分。
MIPS 程序（可以 运行 使用 MARS：http://courses.missouristate.edu/kenvollmar/mars/）：
#Sum and minimum finder; enter 0 to exit
.data
prompt: .asciiz "Input any integer: "
reply1: .asciiz "The sum of all the integers is "
reply2: .asciiz "The minimum value among the integers is "
period: .asciiz "."
newline: .asciiz "\n"
.text
#Register Usage:
# $t0 = current integer input from user
# $t1 = input sum
# $t2 = lowest value so far
# $t3 = minimum value checker bit
# $t4 = loop counter
#Get integer inputs
li $t0 1 #"Initialize" $t0 to 1 to avoid exiting the loop straight away
li $t4 0 #Set the loop counter to 0
loop1: #Begin loop1
beqz $t0 exit1 #Exit loop if integer input is equal to zero
li $v0 4 #Print prompt1
la $a0 prompt
syscall
li $v0 5 #Take user input for prompt
syscall
move $t0 $v0 #Move user input from $v0 to $t0
add $t1 $t0 $t1 #Add integer to input sum
bgt $t4 $zero exit4 #For the first input only, set $t2 to $t0 without any comparisons
add $t2 $t0 $zero
exit4:
ble $t4 $zero exit3 #For all other subsequent inputs, compare the input in $t0 to the current min value in $t2
beqz $t0 exit2 #Do not do this if $t0 is equal to 0
slt $t3 $t2 $t0 #Implement low water mark algorithm, and check if $t2 < $t0
beq $t3 1 statusquo #If $t2 < $t0, then go to statusquo
add $t2 $t0 $zero #If $t0 is less than the current value in $t2, then the status quo is not kept, and the value in $t2 is replaced by the one in $t0
statusquo:
exit2:
exit3:
addi $t4 $t4 1 #Increment first loop counter by one
j loop1 #Repeat loop1
exit1: #Exit loop1
#Print blank space
li $v0 4 #Place a gap between the input and the output
la $a0 newline
syscall
#Print integer input sum
li $v0 4 #Print reply context
la $a0 reply1
syscall
li $v0 1 #Print sum
move $a0 $t1
syscall
li $v0 4 #Print period to end sentence
la $a0 period
syscall
#Print blank space
li $v0 4 #Place a newline here
la $a0 newline
syscall
#Print minimum value
li $v0 4 #Print reply context
la $a0 reply2
syscall
li $v0 1 #Print min value
move $a0 $t2
syscall
li $v0 4 #Print period to end sentence
la $a0 period
syscall
x86 尝试（使用 Irvine 库：https://asmirvine.com/）：
;This program outputs the sum and minimum of the integers entered, enter 0 to quit.
include \irvine\irvine32.inc
includelib \irvine\irvine32.lib
.data
prompt byte "Input any integer: ",0
space byte " ",0
reply1 byte "The sum of all the integers entered is ",0
reply2 byte "The minimum value among the integers entered is ",0
period byte ".",0
newline byte "\n",0 ;?
num dword ?
sum dword ?
min dword ?
minflag dword ?
loopinc dword ?
.code
main proc
mov num, 1 ;initialize num to 1 to avoid exiting the loop right away
mov loopinc, 0
loop1:
test eax, eax
je exit1
mov edx, offset prompt ;print prompt to console
call writestring
call readint ;take num input
mov num, eax ;move input to num variable
add sum, eax ;add input to sum
add loopinc, 1
loop loop1
exit1:
call crlf ;insert newline
mov edx, offset reply1 ;print reply
call writestring
mov edx, sum ;print sum
call writedec
mov edx, offset period ;print period
call writestring
exit
main endp
end main
您使用 WriteDec 不正确。它需要 EAX 中的输入参数，而不是 EDX.
查看文档：https://csc.csudh.edu/mmccullough/asm/help/source/irvinelib/writedec.htm
我正在尝试用 x86 汇编编写一个程序，该程序在输入 0 之前采用整数输入，此时它会打印所有输入的整数之和，以及其中的最小值。我以前在 MIPS 汇编中编写过相同的程序，但是 运行 在 x86 版本中出现错误，其中总和似乎没有在 add 命令中递增。我怎样才能让它工作？我应该直接使用寄存器吗？我已经包含了 MIPS 程序和我在 x86 中的尝试，它还没有最小值部分。
MIPS 程序（可以 运行 使用 MARS：http://courses.missouristate.edu/kenvollmar/mars/）：
#Sum and minimum finder; enter 0 to exit
.data
prompt: .asciiz "Input any integer: "
reply1: .asciiz "The sum of all the integers is "
reply2: .asciiz "The minimum value among the integers is "
period: .asciiz "."
newline: .asciiz "\n"
.text
#Register Usage:
# $t0 = current integer input from user
# $t1 = input sum
# $t2 = lowest value so far
# $t3 = minimum value checker bit
# $t4 = loop counter
#Get integer inputs
li $t0 1 #"Initialize" $t0 to 1 to avoid exiting the loop straight away
li $t4 0 #Set the loop counter to 0
loop1: #Begin loop1
beqz $t0 exit1 #Exit loop if integer input is equal to zero
li $v0 4 #Print prompt1
la $a0 prompt
syscall
li $v0 5 #Take user input for prompt
syscall
move $t0 $v0 #Move user input from $v0 to $t0
add $t1 $t0 $t1 #Add integer to input sum
bgt $t4 $zero exit4 #For the first input only, set $t2 to $t0 without any comparisons
add $t2 $t0 $zero
exit4:
ble $t4 $zero exit3 #For all other subsequent inputs, compare the input in $t0 to the current min value in $t2
beqz $t0 exit2 #Do not do this if $t0 is equal to 0
slt $t3 $t2 $t0 #Implement low water mark algorithm, and check if $t2 < $t0
beq $t3 1 statusquo #If $t2 < $t0, then go to statusquo
add $t2 $t0 $zero #If $t0 is less than the current value in $t2, then the status quo is not kept, and the value in $t2 is replaced by the one in $t0
statusquo:
exit2:
exit3:
addi $t4 $t4 1 #Increment first loop counter by one
j loop1 #Repeat loop1
exit1: #Exit loop1
#Print blank space
li $v0 4 #Place a gap between the input and the output
la $a0 newline
syscall
#Print integer input sum
li $v0 4 #Print reply context
la $a0 reply1
syscall
li $v0 1 #Print sum
move $a0 $t1
syscall
li $v0 4 #Print period to end sentence
la $a0 period
syscall
#Print blank space
li $v0 4 #Place a newline here
la $a0 newline
syscall
#Print minimum value
li $v0 4 #Print reply context
la $a0 reply2
syscall
li $v0 1 #Print min value
move $a0 $t2
syscall
li $v0 4 #Print period to end sentence
la $a0 period
syscall
x86 尝试（使用 Irvine 库：https://asmirvine.com/）：
;This program outputs the sum and minimum of the integers entered, enter 0 to quit.
include \irvine\irvine32.inc
includelib \irvine\irvine32.lib
.data
prompt byte "Input any integer: ",0
space byte " ",0
reply1 byte "The sum of all the integers entered is ",0
reply2 byte "The minimum value among the integers entered is ",0
period byte ".",0
newline byte "\n",0 ;?
num dword ?
sum dword ?
min dword ?
minflag dword ?
loopinc dword ?
.code
main proc
mov num, 1 ;initialize num to 1 to avoid exiting the loop right away
mov loopinc, 0
loop1:
test eax, eax
je exit1
mov edx, offset prompt ;print prompt to console
call writestring
call readint ;take num input
mov num, eax ;move input to num variable
add sum, eax ;add input to sum
add loopinc, 1
loop loop1
exit1:
call crlf ;insert newline
mov edx, offset reply1 ;print reply
call writestring
mov edx, sum ;print sum
call writedec
mov edx, offset period ;print period
call writestring
exit
main endp
end main
您使用 WriteDec 不正确。它需要 EAX 中的输入参数，而不是 EDX.
查看文档：https://csc.csudh.edu/mmccullough/asm/help/source/irvinelib/writedec.htm