我该如何修复 'integrity constraint (PROD_SUP_FK) violated - parent key not found'?
How can I fix 'integrity constraint (PROD_SUP_FK) violated - parent key not found'?
我做到了
INSERT INTO product (prod_id, prod_price, prod_avail, prod_mdate, prod_edate, cust_id, sto_id, sup_id)
Values('RBL01001',4.50,'Available',TO_DATE('29-MAR-21','DD-MON-YY'),TO_DATE('29-APR-21','DD-MON-YY'),0001,'Kapar1','SUPP-001');
这是结果
ORA-02291: integrity constraint (PROD_SUP_FK) violated - parent key not found
ORA-02291: integrity constraint (PROD_SUP_FK) violated - parent key not found
ORA-06512: at "SYS.DBMS_SQL", line 1721
INSERT INTO product (prod_id, prod_price, prod_avail, prod_mdate, prod_edate, cust_id, sto_id, sup_id)
Values('RBL01001',4.50,'Available',TO_DATE('29-MAR-21','DD-MON-YY'),TO_DATE('29-APR-21','DD-MON-YY'),0001,'Kapar1','SUPP-001');
Table 产品
CREATE TABLE product
(
prod_id VARCHAR2 (10) CONSTRAINT prod_id_nn NOT NULL ENABLE,
prod_price NUMBER (3, 2) CONSTRAINT prod_price_nn NOT NULL ENABLE,
prod_avail VARCHAR2 (20) CONSTRAINT prod_avail_nn NOT NULL ENABLE,
prod_mdate DATE CONSTRAINT prod_mdate_nn NOT NULL ENABLE,
prod_edate DATE CONSTRAINT prod_edate_nn NOT NULL ENABLE,
cust_id NUMBER (4, 0),
sto_id VARCHAR (8) CONSTRAINT sto_id_nn NOT NULL ENABLE,
sup_id VARCHAR (10),
CONSTRAINT prod_id_pk PRIMARY KEY (prod_id) USING INDEX ENABLE,
CONSTRAINT prod_date_interval CHECK (prod_edate > prod_mdate) ENABLE
);
table 供应商
CREATE TABLE supplier
(
sup_id VARCHAR2(10) CONSTRAINT sup_id_nn NOT NULL ENABLE,
sup_name VARCHAR2(500) CONSTRAINT sup_name_NN NOT NULL ENABLE,
sup_add VARCHAR2(500) CONSTRAINT sup_add_nn NOT NULL ENABLE,
CONSTRAINT sup_id_pk PRIMARY KEY (sup_id) USING INDEX ENABLE
);
改变table产品
ALTER TABLE product ADD CONSTRAINT prod_cust_fk FOREIGN KEY (cust_id)
REFERENCES customer (cust_id) ENABLE;
ALTER TABLE product ADD CONSTRAINT prod_sto_fk FOREIGN KEY (sto_id)
REFERENCES bakery / store (sto_id) ENABLE;
ALTER TABLE product ADD CONSTRAINT prod_sup_fk FOREIGN KEY (sup_id)
REFERENCES supplier (sup_id) ENABLE;
CREATE INDEX prod_cust_ix ON product (cust_id);
CREATE INDEX prod_sto_ix ON product (sto_id);
CREATE INDEX prod_sup_ix ON product (sup_id);
使用 Oracle APEX 21.2.0
首先,您必须将行插入“master”tables(customer
、supplier
、bakery
/store
),然后插入它们的"child" table (product
).
顺便问一下,这个 bakery / store
应该做什么?这样的语法是无效的:
ALTER TABLE product ADD CONSTRAINT prod_sto_fk FOREIGN KEY (sto_id)
REFERENCES bakery / store (sto_id) ENABLE;
--------------
this
我做到了
INSERT INTO product (prod_id, prod_price, prod_avail, prod_mdate, prod_edate, cust_id, sto_id, sup_id)
Values('RBL01001',4.50,'Available',TO_DATE('29-MAR-21','DD-MON-YY'),TO_DATE('29-APR-21','DD-MON-YY'),0001,'Kapar1','SUPP-001');
这是结果
ORA-02291: integrity constraint (PROD_SUP_FK) violated - parent key not found
ORA-02291: integrity constraint (PROD_SUP_FK) violated - parent key not found
ORA-06512: at "SYS.DBMS_SQL", line 1721
INSERT INTO product (prod_id, prod_price, prod_avail, prod_mdate, prod_edate, cust_id, sto_id, sup_id) Values('RBL01001',4.50,'Available',TO_DATE('29-MAR-21','DD-MON-YY'),TO_DATE('29-APR-21','DD-MON-YY'),0001,'Kapar1','SUPP-001');
Table 产品
CREATE TABLE product
(
prod_id VARCHAR2 (10) CONSTRAINT prod_id_nn NOT NULL ENABLE,
prod_price NUMBER (3, 2) CONSTRAINT prod_price_nn NOT NULL ENABLE,
prod_avail VARCHAR2 (20) CONSTRAINT prod_avail_nn NOT NULL ENABLE,
prod_mdate DATE CONSTRAINT prod_mdate_nn NOT NULL ENABLE,
prod_edate DATE CONSTRAINT prod_edate_nn NOT NULL ENABLE,
cust_id NUMBER (4, 0),
sto_id VARCHAR (8) CONSTRAINT sto_id_nn NOT NULL ENABLE,
sup_id VARCHAR (10),
CONSTRAINT prod_id_pk PRIMARY KEY (prod_id) USING INDEX ENABLE,
CONSTRAINT prod_date_interval CHECK (prod_edate > prod_mdate) ENABLE
);
table 供应商
CREATE TABLE supplier
(
sup_id VARCHAR2(10) CONSTRAINT sup_id_nn NOT NULL ENABLE,
sup_name VARCHAR2(500) CONSTRAINT sup_name_NN NOT NULL ENABLE,
sup_add VARCHAR2(500) CONSTRAINT sup_add_nn NOT NULL ENABLE,
CONSTRAINT sup_id_pk PRIMARY KEY (sup_id) USING INDEX ENABLE
);
改变table产品
ALTER TABLE product ADD CONSTRAINT prod_cust_fk FOREIGN KEY (cust_id)
REFERENCES customer (cust_id) ENABLE;
ALTER TABLE product ADD CONSTRAINT prod_sto_fk FOREIGN KEY (sto_id)
REFERENCES bakery / store (sto_id) ENABLE;
ALTER TABLE product ADD CONSTRAINT prod_sup_fk FOREIGN KEY (sup_id)
REFERENCES supplier (sup_id) ENABLE;
CREATE INDEX prod_cust_ix ON product (cust_id);
CREATE INDEX prod_sto_ix ON product (sto_id);
CREATE INDEX prod_sup_ix ON product (sup_id);
使用 Oracle APEX 21.2.0
首先,您必须将行插入“master”tables(customer
、supplier
、bakery
/store
),然后插入它们的"child" table (product
).
顺便问一下,这个 bakery / store
应该做什么?这样的语法是无效的:
ALTER TABLE product ADD CONSTRAINT prod_sto_fk FOREIGN KEY (sto_id)
REFERENCES bakery / store (sto_id) ENABLE;
--------------
this