MariaDB是否有内置函数使用指定的基数获取整数值进行转换？

Question

MariaDB 是否有内置模拟 PHP intval() or Golang strconv.FormatInt() and strconv.ParseInt() 函数来将 10 位整数值转换为 36 位整数值，反之亦然？我需要在 MariaDB stored procedure.

中调用这些函数

Example on go:

package main

import (
    "fmt"
    "strconv"
)

func main() {
    var (
        i64       int64
        str36base string
        err       error
    )
    i64 = 99999999999999

    str36base = strconv.FormatInt(i64, 36) // from 10-base to 36-base integer
    fmt.Printf("10-base integer: %v --> 36-base integer: %v\n", i64, str36base)

    i64, err = strconv.ParseInt(str36base, 36, 64) // from 36-base to 10-base integer
    if err == nil {
        fmt.Printf("36-base integer: %v --> 10-base integer: %v\n", str36base, i64)
    } else {
        fmt.Println(err.Error())
    }

}

Output:
10-base integer: 99999999999999 --> 36-base integer: zg3d62r5r
36-base integer: zg3d62r5r --> 10-base integer: 99999999999999

Answer 1

猜猜你在找 CONV() ?

https://mariadb.com/kb/en/conv/

SELECT CONV(99999999999999, 10, 36) AS `converted` FROM DUAL;

MariaDB是否有内置函数使用指定的基数获取整数值进行转换？

Have MariaDB built-in function to get the integer value using specified base for the conversion?

mariadb