高级查询盘点日期

Question

我正在尝试编写一个查询，该查询将 return 我的活动 Table 中每个活动的销售日期与非销售日期的订单数量。

订单Table

OrderID (PK, INT)	OrderDate (DATE)	EventID (INT,FK)
1	2022-01-01	1
2	2022-01-12	1
3	2022-01-01	1
4	2022-03-10	2
5	2022-03-15	2

事件Table

EventID (PK, FK, INT)	NameEvent (VARCHAR)	OnSalesDate (DATE)
1	The Rolling Stones	2022-01-01
2	The Who Live in Concert	2022-03-10

输出 Table 应该是这样的

Name_Event	BoughtOnSalesDate	BoughtAfter
The Rolling Stones	2	1
The Who Live in Concert	1	1

我目前的查询是：

SELECT OrderDate , EventName

FROM Orders

Left JOIN Event on Orders.EventID = Event.EventID

WHERE Orders.OrderDate = Event.OnSaleDate

ORDER BY OrderDate;

哪些输出：

OrderDate	EventName
2022-01-01	The Rolling Stones
2022-01-01	The Rolling Stones
2022-03-10	The Who Live in Concert

Answer 1

您可以对事件的数据进行分组以获得您想要的结果

CREATE TABLE Orders  (
  `OrderID` INTEGER,
  `OrderDate` VARCHAR(10),
  `EventID` INTEGER
);

INSERT INTO Orders 
  (`OrderID`, `OrderDate`, `EventID`)
VALUES
  ('1', '2022-01-01', '1'),
  ('2', '2022-01-12', '1'),
  ('3', '2022-01-01', '1'),
  ('4', '2022-03-10', '2'),
  ('5', '2022-03-15', '2');

CREATE TABLE Event  (
  `EventID` INTEGER,
  `NameEvent` VARCHAR(23),
  `OnSalesDate` VARCHAR(10)
);

INSERT INTO Event 
  (`EventID`, `NameEvent`, `OnSalesDate`) 
VALUES
  ('1', 'The Rolling Stones', '2022-01-01'),
  ('2', 'The Who Live in Concert', '2022-03-10');

SELECT `NameEvent`,`OnSalesDate`
, SUM(`OnSalesDate` = `OrderDate`) BoughtOnSalesDate
, SUM(`OnSalesDate` < `OrderDate`)  BoughtAfter
FROM Orders
Left JOIN Event on Orders.EventID = Event.EventID
GROUP  BY Orders.`EventID`, `NameEvent`,`OnSalesDate`
ORDER BY `OnSalesDate`;

NameEvent               | OnSalesDate | BoughtOnSalesDate | BoughtAfter
:---------------------- | :---------- | ----------------: | ----------:
The Rolling Stones      | 2022-01-01  |                 2 |           1
The Who Live in Concert | 2022-03-10  |                 1 |           1

db<>fiddle here

高级查询盘点日期

Advanced Query Counting Dates

mysql

sql

join