使用基于 Access 中另一个 table 的计算字段进行查询

Query with a calculated field based on another table in Access

我有两个具有以下值的 Microsoft Access table:

Devices

| N    | Desc   | O | P |
+------+--------+---+---+
| 3560 | ABC    | 0 | 0 | <-
| 3559 | DEF    | 0 | 1 |
| 3558 | GHI    | 1 | 0 |
| 3557 | JKL    | 1 | 0 |
| 3548 | MNO    | 0 | 0 | <-
| 3549 | PQR    | 0 | 0 | <-
| 3540 | STU    | 0 | 0 | <-

Notifications

id | N    | Email       |
---+------+-------------+
1  | 3559 | a@dom.loc   | <-
2  | 3548 | a@dom.loc   | <-
3  | 3548 | b@dom.loc   |
4  | 3547 | b@dom.loc   |
5  | 3549 | b@dom.loc   |

我想提取所有 Devices 包含 O = 0P = 0 的记录并添加一个名为 计算字段 ]已订阅。仅当 Notifications table 中存在相同的 N 且我作为参数提供的 Email 时,此字段才必须为 True 并且False否则。

有例如 Email = a@dom.loc 参数(即为此目的在 SQL 中硬编码),那么这应该是所需的结果:

| N    | Desc   | O | P | Subscribed |
+------+--------+---+---+------------+
| 3560 | ABC    | 0 | 0 | False      |
| 3548 | MNO    | 0 | 0 | True       |
| 3549 | PQR    | 0 | 0 | False      |
| 3540 | STU    | 0 | 0 | False      |

考虑到这两个 table 将来可能会很大,我如何在 Access 中执行此查询?

可能我错过了子查询 SQL,这个有效:

SELECT Devices.N, Devices.Desc, Devices.O, Devices.P,
(SELECT Count(*) FROM Notifications
WHERE Notifications.N = Devices.N
AND Notifications.Email = "a@dom.loc") > 0 AS Subscribed
FROM Devices
WHERE ((Devices.O=0) AND (Devices.P=0))

编辑:@iDevlop 发表评论后,我能够正确创建 LEFT JOIN 变体,谢谢!

SELECT Devices.N, Devices.Desc, Devices.O, Devices.P, Not IsNull(Id) AS Subscribed
FROM Devices
LEFT JOIN (SELECT Notifications.N, Notifications.Id
FROM Notifications
WHERE (Notifications.Email = "a@dom.loc")) AS qNotif
ON Devices.N = qNotif.N
WHERE ((Devices.O=0) AND (Devices.P=0));