do-while 斐波那契数列重复答案

Question

我做了一个关于斐波那契数列的程序。我想重复这个程序，所以我使用了 do-while 循环。但是，似乎上一个结果的最后两个数字不断出现。它应该重置回第一个任期。请帮助我如何到达那里。

#include<iostream>    
using namespace std;      
void printFibonacci(int n){    
    static int n1=1, n2=1, n3=0;    
    if(n>0){
         n3 = n1 + n2;    
         n1 = n2;    
         n2 = n3;    
 cout<<n3<<" ";    
         printFibonacci(n);    
    }    
}    
int main(){    
    int n;    
    cout<<"Enter the number of elements: ";    
    cin>>n;    
    cout<<"Fibonacci Series: ";    
    cout<<"0 "<<"1 ";  
    printFibonacci(n-2);  //n-2 because 2 numbers are already printed    
     return 0;  
}

Answer 1

你的代码的问题是你没有在循环结束后重置你的变量。因此，要解决此问题，只需在 do-while 循环中定义您的变量：

do {
    int t1 = 1, t2 = 1, nextTerm = 0;

..或在 1 个循环完成后重置您的变量：

else {
    cout << "Thank you for using the program." << endl;
}

t1 = 1, t2 = 1, nextTerm = 0;

但是 n 必须在循环外定义（正如您所做的那样）：

std::cout << "Fibonacci Program" << std::endl;

int n;
do {

也不需要创建变量i:

int /*i,*/ t1 = 1, t2 = 1, nextTerm = 0;

..因为您稍后在此处的 for 循环中创建了它：

for (int i = 1; i <= n; ++i) {

此外，请考虑不要在您的代码中使用以下内容：

using namespace std;

..因为它被认为是一种不好的做法。有关这方面的更多信息，请查看 why is using namespace std considered a bad practice.

Answer 2

当您第一次运行编写代码时，变量 t1、t2 和 nextTerm 的值正在发生变化。因此，在再次重复相同的代码之前，您需要再次设置这些变量的默认值。简单地试试这个：

#include <iostream>
using namespace std;
int main (){
    int i, n, t1=1, t2=1, nextTerm=0;
    cout << "Fibonacci Program" << endl;
    do{
        t1=1;
        t2=2;
        nextTerm=0;
        cout << "How many elements? ";
        cin >> n;
        if(n>=1){
            cout << "Sequence: ";
            for (int i = 1; i <= n; ++i){
                  if(i == 1) {
                    cout << t1 << " ";
                    continue;
                }
                  if(i == 2) {
                    cout << t2 << " ";
                    continue;
                }
                nextTerm = t1 + t2;
                t1 = t2;
                t2 = nextTerm;
                cout << nextTerm << " ";
            }
            cout << endl;
        }
        else{
            cout << "Thank you for using the program." << endl;
        }
    }
    while(n>=1);
    return 0;
}

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