根据键（浮点值）比较和删除列表对象

Question

我有一个对象列表“repeated_words_list”，每个对象都包含一个字典，其中包含单词（字符串）、开始（浮动）、结束（浮动）、conf（浮动）

我只想保留所有出现次数中 p.start 最高的每个重复单词出现 1 次，并删除所有 p.start 较低的出现次数。

我打印出来是这样的

for p in repeated_words_list:
    print(f"{p.word} {p.start} - {p.end}")

输出

p.word p.start - p.end
the 0.27 - 2.91
the 25.38 - 25.5
the 26.94 - 27.24
the 27.66 - 27.81
the 38.67 - 38.705229
the 53.22 - 53.73
the 55.02 - 55.17
well 2.91 - 3.39
well 3.96 - 4.38
well 5.82 - 6.09
well 9.09 - 9.42
well 12.21 - 12.63
keeping 4.53 - 4.95
keeping 13.2 - 13.53
yourself 4.95 - 5.43
yourself 13.53 - 14.04
it 6.09 - 6.24
it 56.67 - 56.88
can 6.24 - 6.57
can 21.09 - 21.48
is 15.81 - 16.05
is 25.86 - 26.04
is 28.14 - 28.26
a 16.05 - 16.14
a 22.862336 - 22.89
see 54.764476 - 55.02
whether 61.35 - 61.71
whether 63.63 - 63.93
it's 61.71 - 62.07
it's 63.93 - 64.17

我尝试过这种方式，但无法完成此操作，因为我无法访问上一个和下一个元素。

for i in range(len(repeated_words_list)):
    if p[i].word == p[i-1].word:
        if p[i].start > p[i-1].start:
            repeated_words_list[i-1]= p[i].start

有好心人可以指导我吗？提前致谢！

Answer 1

创建一个使用 word 作为索引的字典。如果索引已经存在，只有在找到更高的 start 值时才更新该值。

final_words = {}
for p in repeated_words_list:
    word = final_words.get(p.word, None)
    if not word:
        final_words[p.word] = p 
    else:
        if word.start < p.start:
            final_words[p.word] = p

# to get highest values
for p in final_words.values():
    print(f"{p.word} {p.start} - {p.end}")

# for all words other than the one with highest occurence
for p in repeated_words_list:
    if final_words[p.word] != p:
        print(f"{p.word} {p.start} - {p.end}")

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