在 python 中将数组值递增 1
incrementing array value by one in python
在代码中,我需要将“age”递增 1,而“age”需要从 24 开始。我正在考虑制作另一个函数,该函数将输入 def getResults 并将“age”递增 1那个功能。不知道该怎么做。对此很陌生。请帮忙。谢谢!
import pprint
def getResults():
mylist = []
for n in range(1, 37 + 1):
currentRow = {"age": n, "numOfYears": n,
"beginningBalance": n, "currentSalary": 72_000.00,
"dividendsAndGrowth": n, "yearlyDeposit": 8_640.00,
"yearlyTotal": n}
mylist.append(currentRow)
return mylist
if __name__ == "__main__":
z = getResults()
pprint.pprint(z)
这是您要找的吗?
import pprint
def getResults():
mylist = []
for n in range(1, 37 + 1):
currentRow = {"age": 23+n, "numOfYears": n,
"beginningBalance": n, "currentSalary": 72_000.00,
"dividendsAndGrowth": n, "yearlyDeposit": 8_640.00,
"yearlyTotal": n}
mylist.append(currentRow)
return mylist
if __name__ == "__main__":
z = getResults()
pprint.pprint(z)
在代码中,我需要将“age”递增 1,而“age”需要从 24 开始。我正在考虑制作另一个函数,该函数将输入 def getResults 并将“age”递增 1那个功能。不知道该怎么做。对此很陌生。请帮忙。谢谢!
import pprint
def getResults():
mylist = []
for n in range(1, 37 + 1):
currentRow = {"age": n, "numOfYears": n,
"beginningBalance": n, "currentSalary": 72_000.00,
"dividendsAndGrowth": n, "yearlyDeposit": 8_640.00,
"yearlyTotal": n}
mylist.append(currentRow)
return mylist
if __name__ == "__main__":
z = getResults()
pprint.pprint(z)
这是您要找的吗?
import pprint
def getResults():
mylist = []
for n in range(1, 37 + 1):
currentRow = {"age": 23+n, "numOfYears": n,
"beginningBalance": n, "currentSalary": 72_000.00,
"dividendsAndGrowth": n, "yearlyDeposit": 8_640.00,
"yearlyTotal": n}
mylist.append(currentRow)
return mylist
if __name__ == "__main__":
z = getResults()
pprint.pprint(z)