从 yml 获取变量值并传递给 shell 脚本？

Question

data.yml

variables:
  count: "100"
  name: "sss"
  pass: "123"

file.sh

#!/bin/bash
echo "Details are "$name":"$pass" - Total value "$count"

我需要从 data.yml 获取变量值并传递给 file.sh

调用 file.sh 应该给出输出：

Details are sss:123 - Total value 100

Answer 1

有一个cli工具yq可以解析yaml文件。

脚本如下所示：

#!/usr/bin/env bash
name=$(yq '.variables.name' data.yaml)
pass=$(yq '.variables.pass' data.yaml)
count=$(yq '.variables.count' data.yaml)

echo "Details are $name: $pass - Total value $count"

当然你也可以将文件作为参数传递。

Answer 2

您可以使用对 yq 的单个调用并将值放入数组中：

#!/usr/bin/env bash
  
mapfile -t array < <(yq '.variables[]' data.yml)
declare -p array

Answer 3

从yq中读取名称值对并使用bashprintf -v初始化变量。有点过头了，但是初始化脚本的好方法。请注意，添加变量不会更改 while 循环。

file.sh

#!/bin/bash

while read -r key val; do
    printf -v "$key" "$val"
done < <(yq -r '.variables | keys[] as $k | "\($k) \(.[$k])"' data.yml)

echo "Details are $name: $pass - Total value $count"
echo 'Some extra variables:'
echo "$address: $address, $phone: $phone, $url: $url"

data.yml

variables:
  count: "100"
  name: "sss"
  pass: "123"
  address: "42 Terrapin Station"
  phone: "999-999-9999"
  url: "http://www.examle.com"

输出

Details are sss: 123 - Total value 100
Some extra variables:
$address: 42 Terrapin Station, $phone: 999-999-9999, $url: http://www.examle.com

从 yml 获取变量值并传递给 shell 脚本？

Fetch variables values from yml and pass to shell script?

bash

yaml