Python return 包含多个单词列表的消息

Question

我正在 discord 上制作一个非常简单的机器人，return 如果机器人读取简单的单词，无论发送者是谁，都会收到一条消息。如果机器人在第二个列表中读到另一个词，我希望它 return 发送第二条消息。

事实上，如果有人输入“WORD 2”，它 return 完美“MESSAGE 2”，但它不适用于“WORD 1”和“MESSAGE 1”，没有任何反应。

我的代码如下：

import discord
from discord.ext import commands
from discord.utils import get
from discord.ext.commands import Bot

client = commands.Bot(command_prefix = ".")

class Myclient(discord.Client):
    async def on_ready(self):
        print('Logged on as', self.user)

    async def on_message(self, message):
        word_list = ['WORD 1']
        # don't respond to ourselves
        if message.author == self.user:
            return
        messageContent = message.content
        if len(messageContent) > 0:
            for word in word_list:
                if word in messageContent:
                    await message.channel.send('MESSAGE 1 @everyone')

    async def on_message(self, message):
        word_list = ['WORD2']
        # don't respond to ourselves
        if message.author == self.user:
            return
        messageContent = message.content
        if len(messageContent) > 0:
            for word in word_list:
                if word in messageContent:
                    await message.channel.send('MESSAGE 2 @everyone')

client = Myclient()
client.run('my token here')

Answer 1

你不能有两个这样的 on_message 函数；第二个定义将覆盖第一个。对于这种功能，您必须有一个 on_message 方法来检查消息是什么，然后根据消息内容执行任何您想要的操作。

Answer 2

您可以做的是简单地使用 dict 将匹配的词映射到响应消息：

    async def on_message(self, message):
        response_map = {'WORD1': 'MESSAGE 1 @everyone', 'WORD2':'MESSAGE 2 @everyone'}
        # don't respond to ourselves
        if message.author == self.user:
            return
        messageContent = message.content
        if len(messageContent) > 0:
            for word, message in response_map:
                if word in messageContent:
                    await message.channel.send(message)

Answer 3

如果这不是一个好的编码方式，我很抱歉，但我是新手，没有经验。但是，这为我解决了这个问题：

    async def on_message(self, message):
        word_list1 = ['WORD1']
        word_list2 = ['WORD2']
        # don't respond to ourselves
        if message.author == self.user:
            return
        messageContent = message.content
        if len(messageContent) > 0:
            for word in word_list1:
                if word in messageContent:
                    await message.channel.send('MESSAGE 1 @everyone')
        if message.author == self.user:
                return
        messageContent = message.content
        if len(messageContent) > 0:
            for word in word_list2:
                if word in messageContent:
                    await message.channel.send('MESSAGE 2 @everyone')

Python return 包含多个单词列表的消息

Python return message with multiple word list

python

discord