Mapstruct

Question

我有两个映射器 class，如下所示。


@Mapper
public interface CountryLanguageMapper {

    CountryLanguageMapper INSTANCE = Mappers.getMapper(CountryLanguageMapper.class);

    List<CountryLanguageResponse> toResponseList(List<CountryLanguage> source);

    @Mapping(target = "languageId", source = "id.language.id")
    CountryLanguageResponse toResponse(CountryLanguage source);

}


@Mapper
public interface CountryMapper {

    CountryMapper INSTANCE = Mappers.getMapper(CountryMapper.class);

    List<CountryListResponse> toResponseList(List<Country> source);

    @Mapping(target = "languages", source = "countryLanguages") // how should it be?
    CountryResponse toResponse(Country source);

    CountryListResponse toListResponse(Country source);

    @Mapping(target = "languages", source = "countryLanguages")
    CountryCreateResponse toCreateResponse(Country source);

    Country fromCreateRequest(CountryCreateRequest source);

    void updateFromUpdateRequest(CountryUpdateRequest source, @MappingTarget Country target);

}

我可以让 CountryMapper#toResponse 方法在映射 countryLanguages 字段时使用 CountryLanguageMapper#toResponseList 方法吗？

如果不可能，我如何在不在 CountryMapper 中编写自定义映射方法的情况下将“countryLanguages.id.language.id”映射到“languages.languageId”？

按如下方式编辑 CountryMapper class 对我有用。但是我想知道是否有办法在不同的映射器中使用一个方法。

@Mapper
public interface CountryMapper {

    CountryMapper INSTANCE = Mappers.getMapper(CountryMapper.class);

    List<CountryListResponse> toResponseList(List<Country> source);

    @Mapping(target = "languages", source = "countryLanguages", qualifiedByName = "toCountryLanguageResponseList")
    CountryResponse toResponse(Country source);

    CountryListResponse toListResponse(Country source);

    @Mapping(target = "languages", source = "countryLanguages")
    CountryCreateResponse toCreateResponse(Country source);

    @Mapping(target = "id", ignore = true)
    Country fromCreateRequest(CountryCreateRequest source);

    void updateFromUpdateRequest(CountryUpdateRequest source, @MappingTarget Country target);

    @IterableMapping(qualifiedByName = "toCountryLanguageResponse")
    @Named("toCountryLanguageResponseList")
    List<CountryLanguageResponse> toCountryLanguageResponseList(Collection<CountryLanguage> source);

    @Mapping(target = "languageId", source = "id.language.id")
    @Named("toCountryLanguageResponse")
    CountryLanguageResponse toCountryLanguageResponse(CountryLanguage source);

}

提前致谢:)

Answer 1

这可以通过 uses 指令实现。

例如：

@Mapper(uses=CountryLanguageMapper.class)
public interface CountryMapper {

有关详细信息，请参见此处： https://mapstruct.org/documentation/dev/reference/html/#invoking-other-mappers

Mapstruct - 使用不同映射器中的方法映射对象的列表项

Mapstruct - Mapping an object's list item with a method in a different mapper

java

spring-boot