尝试将二维数组传递给函数并出现编译器错误

Question

我是 C/C++ 初学者，正在尝试构建一个简单的脚本。我在 Arduino 上运行这个。

#include <Arduino.h>

int pin_locations[3][3] = {
  {8,  5, 4},
  {9,  6, 3},
  {10, 7, 2}
};

void setup() {
  for (int i=0; i<3; ++i) {
    for (int j=0; j<3; ++j) {
      pinMode(pin_locations[i][j], OUTPUT);
    }
  }
}

void convert_drawing_to_LEDS(int drawing[]) {
  for (int i=0; i<3; ++i) {
    for (int j=0; j<3; ++j) {
      if (drawing[i][j] == 1) {
        digitalWrite(pin_locations[i][j], HIGH);
      }
    }
  }
}

void loop() {
  // drawing
  int my_drawing[3][3] = {
    {1, 1, 1},
    {1, 0, 1},
    {1, 1, 1}
  };

  convert_drawing_to_LEDS(my_drawing);

}

但是它给了我两个错误：

src/main.cpp: In function 'void convert_drawing_to_LEDS(int*)': src/main.cpp:31:23: error: invalid types 'int[int]' for array subscript if (drawing[i][j] == 1) { ^ src/main.cpp: In function 'void loop()': src/main.cpp:46:37: error: cannot convert 'int ()[3]' to 'int' for argument '1' to 'void convert_drawing_to_LEDS(int*)'
convert_drawing_to_LEDS(my_drawing); ^ Compiling .pio/build/uno/FrameworkArduino/WInterrupts.c.o *** [.pio/build/uno/src/main.cpp.o] Error

谁能帮帮我？

谢谢！

Answer 1

您已声明 convert_drawing_to_LEDS 取一个 int []，它不是二维数组。这会导致参数与其在函数中的使用方式不匹配，以及传入的实际参数与函数期望的参数不匹配。

你反而想要：

void convert_drawing_to_LEDS(int drawing[3][3]) {

尝试将二维数组传递给函数并出现编译器错误

Trying to pass 2D array to function and getting a compiler error

c++

c

arduino