在 json 和 return 主键中搜索值

Question

我有一个 json 结构像这样

{
  "india": {
    "north_states": ["TN", "AP", "MP", "AB"],
    "south_states": ["PB", "UP", "RJ", "HR"]
  },
  "us": {
    "north_states": ["AC", "AD", "AE", "AF"],
    "south_states": ["BA", "BB", "BC", "BD"]
  },
}

现在如果我搜索“UP”，我必须得到 south_states 和 india 作为回复。我如何在 JavaScript 中做到这一点？

例如：

我需要根据搜索中给出的输入获取国家/地区名称。例如，如果我得到的输入值为 'UP'，我需要搜索 UP 所在的 json 并获取它的键 (south_states)，我还需要将国家/地区名称设为印度。结果应采用州首字母缩写名称的输入，并将键作为国家名称和 state_location（南或北）

Answer 1

我会以这种方式迭代：

代码可能需要一些调整，但它有效。

这使用递归来迭代 JSON 以找到匹配的 objects/array。如果JSON的结构是固定的，那就更简单了。

const countries = { "india":{"north_states":["TN","AP","MP","AB"],"south_states":["PB","UP","RJ","HR"]}, "us":{"north_states":["AC","AD","AE","AF"],"south_states":["BA","BB","BC","BD"]}, };


function findItems(data, value, pkey){
  let results = [];
  for(let key of Object.keys(data)){
      let newData = data[key];
      if(typeof(newData) == 'string'){
          if(newData == value){
            results.push(pkey);
          }
      } else {
        results = findItems(newData, value, key).concat(results);
      }
  }
  if(results.length > 0 && pkey && results.indexOf(pkey) == -1){
    results.push(pkey);
  }
  return results;
}

let search = findItems(countries, 'UP');

console.info(search);

对于固定结构，只应找到结果：

    const countries = { "india":{"north_states":["TN","AP","MP","AB"],"south_states":["PB","UP","RJ","HR"]}, "us":{"north_states":["AC","AD","AE","AF"],"south_states":["BA","BB","BC","BD"]}, };


    function findItems(data, searchTerm){
      let results = [];
      for(let country of Object.keys(data)){
          let stateGroups = data[country];
          for(let stateGroupName of Object.keys(stateGroups)){
            let stateGroup = stateGroups[stateGroupName];
            if(stateGroup.indexOf(searchTerm)!=-1){
              return [country, stateGroupName];
            }
          }
      }
     
    }

    let search = findItems(countries, 'UP');

    console.info(search);

Answer 2

Parse the JSON 转换为可以循环的 JS 对象。
Loop over the main object properties, and then loop over each of those object's properties, and if any of those arrays includes你要匹配的值，return主对象的key，内层对象的key。

const json = '{"india":{"north_states":["TN","AP","MP","AB"],"south_states":["PB","UP","RJ","HR"]},"us":{"north_states":["AC","AD","AE","AF"],"south_states":["BA","BB","BC","BD"]}}';

const data = JSON.parse(json);

function check(data, val) {
  for (let key in data) {
    for (let innerkey in data[key]) {
      if (data[key][innerkey].includes(val)) {
        return [key, innerkey];
      }
    }
  }
  return 'No match';
}

console.log(check(data, 'UP'));
console.log(check(data, 'BO'));
console.log(check(data, 'AF'));

在 json 和 return 主键中搜索值

search for value in json and return the main key

javascript

json

destructuring

web