是否可以输出 table 按组排序且每个组有限？
Is it possible to output table ordered by group and limited per group?
我有一个包含 table 辆汽车的数据库，table 有许多不同的列。我需要输出每辆汽车品牌订购的 table 中的内容，每个品牌只需要输出三辆汽车以及每排汽车的总数。我还需要按降序排列输出，并附有一个名为 Ranking 的列，该列从 1 递增到将有多少个输出。
下面是我的数据库中的示例 table
|Timestamp |Email |Name |Year|Make |Model |Car_ID|Judge_ID|Judge_Name|Racer_Turbo|Racer_Supercharged|Racer_Performance|Racer_Horsepower|Car_Overall|Engine_Modifications|Engine_Performance|Engine_Chrome|Engine_Detailing|Engine_Cleanliness|Body_Frame_Undercarriage|Body_Frame_Suspension|Body_Frame_Chrome|Body_Frame_Detailing|Body_Frame_Cleanliness|Mods_Paint|Mods_Body|Mods_Wrap|Mods_Rims|Mods_Interior|Mods_Other|Mods_ICE|Mods_Aftermarket|Mods_WIP|Mods_Overall|
|--------------|-------------------------|----------|----|--------|---------|------|--------|----------|-----------|------------------|-----------------|----------------|-----------|--------------------|------------------|-------------|----------------|------------------|------------------------|---------------------|-----------------|--------------------|----------------------|----------|---------|---------|---------|-------------|----------|--------|----------------|--------|------------|
|8/5/2018 14:10|honoland13@japanpost.jp |Hernando |2015|Acura |TLX |48 |J04 |Bob |0 |0 |2 |2 |4 |4 |0 |2 |4 |4 |2 |4 |2 |2 |2 |2 |2 |0 |4 |4 |4 |6 |2 |0 |4 |
|8/5/2018 15:11|nlighterness2q@umn.edu |Noel |2015|Jeep |Wrangler |124 |J02 |Carl |0 |6 |4 |2 |4 |6 |6 |4 |4 |4 |6 |6 |6 |6 |6 |4 |6 |6 |6 |6 |6 |4 |6 |4 |6 |
|8/5/2018 17:10|eguest47@microsoft.com |Edan |2015|Lexus |Is250 |222 |J05 |Adrian |0 |0 |0 |0 |0 |0 |0 |0 |6 |6 |6 |0 |0 |6 |6 |6 |0 |0 |0 |0 |0 |0 |0 |0 |4 |
|8/5/2018 17:34|hchilley40@fema.gov |Hieronymus|1993|Honda |Civic eG |207 |J06 |Aaron |0 |0 |2 |2 |2 |2 |2 |2 |0 |4 |2 |2 |2 |2 |2 |2 |4 |2 |2 |0 |0 |0 |2 |2 |0 |
|8/5/2018 14:30|nnowick3d@tuttocitta.it |Nickolas |2016|Ford |Mystang |167 |J02 |Carl |0 |0 |2 |2 |0 |2 |2 |0 |0 |0 |0 |2 |0 |2 |2 |2 |0 |0 |2 |0 |0 |0 |0 |0 |2 |
|8/5/2018 16:12|mdearl39@amazon.co.uk |Martin |2013|Hyundai |Gen coupe|159 |J04 |Bob |0 |0 |2 |0 |0 |0 |2 |0 |0 |0 |0 |2 |0 |2 |2 |0 |2 |0 |2 |0 |0 |0 |0 |0 |0 |
|8/5/2018 17:00|alynamg@blogtalkradio.com|Aldridge |2009|Infiniti|G37 |20 |J06 |Aaron |2 |0 |2 |2 |0 |0 |2 |0 |0 |2 |2 |2 |2 |2 |2 |2 |2 |2 |4 |2 |2 |0 |2 |0 |2 |
|8/5/2018 16:11|abowton3k@spiegel.de |Ambros |2009|Honda |Oddesy |178 |J06 |Aaron |2 |0 |2 |2 |2 |2 |2 |0 |4 |4 |2 |2 |2 |4 |4 |4 |2 |2 | |6 |4 |4 |6 |4 |6 |
|8/5/2018 17:29|qesterbrookn@bandcamp.com|Quincy |2012|Hyundai |Celoster |30 |J04 |Bob |0 |0 |2 |2 |2 |2 |2 |4 |6 |6 |4 |2 |4 |4 |6 |6 |4 |0 |2 |0 |0 |0 |2 |2 |4 |
预期的输出如下所示
|Ranking |Car_ID|Year |Make |Model |Total|
|--------|------|-------|------|-----------|-----|
|1 |48 |2015 |Acura |TLX |89 |
|2 |66 |2012 |Acura |MDX |75 |
|3 |101 |2022 |Acura |TLX |70 |
|4 |22 |2011 |Chevy |Camaro |112 |
|5 |40 |2015 |Chevy |Corvette |99 |
|6 |205 |2022 |Chevy |Corvette |66 |
|7 |111 |2006 |Ford |Mustang |94 |
|8 |97 |2003 |Ford |GT |88 |
|9 |71 |2008 |Ford |Fiesta ST |80 |
这是我能够组合起来的命令，它执行的操作与我需要的类似，但我无法弄清楚如何按总数降序排列排名列和顺序。
SELECT Car_ID, Year, Make, Model, Racer_Turbo + Racer_Supercharged + ... + Mods_Overall FROM Carstable order by Make limit 3;
这个查询命令只返回了三个结果，而不是全部，我也想不通应该把DESC关键字放在命令的什么地方，才能让它们根据总列降序排列或者怎么办排名栏也是如此。有什么想法吗？
使用 CTE，其中 returns 每一行的列 Total 和 ROW_NUMBER() window 函数为每个 Make 选择前 3 行和创建列 Ranking:
WITH cte AS (
SELECT *,
Racer_Turbo + Racer_Supercharged + Racer_Performance + Racer_Horsepower +
Car_Overall +
Engine_Modifications + Engine_Performance + Engine_Chrome + Engine_Detailing + Engine_Cleanliness +
Body_Frame_Undercarriage + Body_Frame_Suspension + Body_Frame_Chrome + Body_Frame_Detailing + Body_Frame_Cleanliness +
Mods_Paint + Mods_Body + Mods_Wrap + Mods_Rims + Mods_Interior + Mods_Other + Mods_ICE + Mods_Aftermarket + Mods_WIP + Mods_Overall Total
FROM carstable
)
SELECT ROW_NUMBER() OVER (ORDER BY Make, Total DESC) Ranking,
Car_ID, Year, Make, Model, Total
FROM (SELECT *, ROW_NUMBER() OVER (PARTITION BY Make ORDER BY Total) rn FROM cte)
WHERE rn <= 3
ORDER BY Make, Total DESC;
参见demo。
我有一个包含 table 辆汽车的数据库，table 有许多不同的列。我需要输出每辆汽车品牌订购的 table 中的内容，每个品牌只需要输出三辆汽车以及每排汽车的总数。我还需要按降序排列输出，并附有一个名为 Ranking 的列，该列从 1 递增到将有多少个输出。
下面是我的数据库中的示例 table
|Timestamp |Email |Name |Year|Make |Model |Car_ID|Judge_ID|Judge_Name|Racer_Turbo|Racer_Supercharged|Racer_Performance|Racer_Horsepower|Car_Overall|Engine_Modifications|Engine_Performance|Engine_Chrome|Engine_Detailing|Engine_Cleanliness|Body_Frame_Undercarriage|Body_Frame_Suspension|Body_Frame_Chrome|Body_Frame_Detailing|Body_Frame_Cleanliness|Mods_Paint|Mods_Body|Mods_Wrap|Mods_Rims|Mods_Interior|Mods_Other|Mods_ICE|Mods_Aftermarket|Mods_WIP|Mods_Overall|
|--------------|-------------------------|----------|----|--------|---------|------|--------|----------|-----------|------------------|-----------------|----------------|-----------|--------------------|------------------|-------------|----------------|------------------|------------------------|---------------------|-----------------|--------------------|----------------------|----------|---------|---------|---------|-------------|----------|--------|----------------|--------|------------|
|8/5/2018 14:10|honoland13@japanpost.jp |Hernando |2015|Acura |TLX |48 |J04 |Bob |0 |0 |2 |2 |4 |4 |0 |2 |4 |4 |2 |4 |2 |2 |2 |2 |2 |0 |4 |4 |4 |6 |2 |0 |4 |
|8/5/2018 15:11|nlighterness2q@umn.edu |Noel |2015|Jeep |Wrangler |124 |J02 |Carl |0 |6 |4 |2 |4 |6 |6 |4 |4 |4 |6 |6 |6 |6 |6 |4 |6 |6 |6 |6 |6 |4 |6 |4 |6 |
|8/5/2018 17:10|eguest47@microsoft.com |Edan |2015|Lexus |Is250 |222 |J05 |Adrian |0 |0 |0 |0 |0 |0 |0 |0 |6 |6 |6 |0 |0 |6 |6 |6 |0 |0 |0 |0 |0 |0 |0 |0 |4 |
|8/5/2018 17:34|hchilley40@fema.gov |Hieronymus|1993|Honda |Civic eG |207 |J06 |Aaron |0 |0 |2 |2 |2 |2 |2 |2 |0 |4 |2 |2 |2 |2 |2 |2 |4 |2 |2 |0 |0 |0 |2 |2 |0 |
|8/5/2018 14:30|nnowick3d@tuttocitta.it |Nickolas |2016|Ford |Mystang |167 |J02 |Carl |0 |0 |2 |2 |0 |2 |2 |0 |0 |0 |0 |2 |0 |2 |2 |2 |0 |0 |2 |0 |0 |0 |0 |0 |2 |
|8/5/2018 16:12|mdearl39@amazon.co.uk |Martin |2013|Hyundai |Gen coupe|159 |J04 |Bob |0 |0 |2 |0 |0 |0 |2 |0 |0 |0 |0 |2 |0 |2 |2 |0 |2 |0 |2 |0 |0 |0 |0 |0 |0 |
|8/5/2018 17:00|alynamg@blogtalkradio.com|Aldridge |2009|Infiniti|G37 |20 |J06 |Aaron |2 |0 |2 |2 |0 |0 |2 |0 |0 |2 |2 |2 |2 |2 |2 |2 |2 |2 |4 |2 |2 |0 |2 |0 |2 |
|8/5/2018 16:11|abowton3k@spiegel.de |Ambros |2009|Honda |Oddesy |178 |J06 |Aaron |2 |0 |2 |2 |2 |2 |2 |0 |4 |4 |2 |2 |2 |4 |4 |4 |2 |2 | |6 |4 |4 |6 |4 |6 |
|8/5/2018 17:29|qesterbrookn@bandcamp.com|Quincy |2012|Hyundai |Celoster |30 |J04 |Bob |0 |0 |2 |2 |2 |2 |2 |4 |6 |6 |4 |2 |4 |4 |6 |6 |4 |0 |2 |0 |0 |0 |2 |2 |4 |
预期的输出如下所示
|Ranking |Car_ID|Year |Make |Model |Total|
|--------|------|-------|------|-----------|-----|
|1 |48 |2015 |Acura |TLX |89 |
|2 |66 |2012 |Acura |MDX |75 |
|3 |101 |2022 |Acura |TLX |70 |
|4 |22 |2011 |Chevy |Camaro |112 |
|5 |40 |2015 |Chevy |Corvette |99 |
|6 |205 |2022 |Chevy |Corvette |66 |
|7 |111 |2006 |Ford |Mustang |94 |
|8 |97 |2003 |Ford |GT |88 |
|9 |71 |2008 |Ford |Fiesta ST |80 |
这是我能够组合起来的命令，它执行的操作与我需要的类似，但我无法弄清楚如何按总数降序排列排名列和顺序。
SELECT Car_ID, Year, Make, Model, Racer_Turbo + Racer_Supercharged + ... + Mods_Overall FROM Carstable order by Make limit 3;
这个查询命令只返回了三个结果，而不是全部，我也想不通应该把DESC关键字放在命令的什么地方，才能让它们根据总列降序排列或者怎么办排名栏也是如此。有什么想法吗？
使用 CTE，其中 returns 每一行的列 Total 和 ROW_NUMBER() window 函数为每个 Make 选择前 3 行和创建列 Ranking:
WITH cte AS (
SELECT *,
Racer_Turbo + Racer_Supercharged + Racer_Performance + Racer_Horsepower +
Car_Overall +
Engine_Modifications + Engine_Performance + Engine_Chrome + Engine_Detailing + Engine_Cleanliness +
Body_Frame_Undercarriage + Body_Frame_Suspension + Body_Frame_Chrome + Body_Frame_Detailing + Body_Frame_Cleanliness +
Mods_Paint + Mods_Body + Mods_Wrap + Mods_Rims + Mods_Interior + Mods_Other + Mods_ICE + Mods_Aftermarket + Mods_WIP + Mods_Overall Total
FROM carstable
)
SELECT ROW_NUMBER() OVER (ORDER BY Make, Total DESC) Ranking,
Car_ID, Year, Make, Model, Total
FROM (SELECT *, ROW_NUMBER() OVER (PARTITION BY Make ORDER BY Total) rn FROM cte)
WHERE rn <= 3
ORDER BY Make, Total DESC;
参见demo。