尝试访问不安全的路由时出错

Question

我在我的 java 项目中使用 spring 安全性来保护 Web 服务。我所有的 Web 服务都在这里受到保护，是我使用的过滤器链配置：

@Override
protected void configure(HttpSecurity http) throws Exception {
    http
            .cors().and()
            .csrf().disable()
            .sessionManagement()
            .sessionCreationPolicy(SessionCreationPolicy.STATELESS)
            .and()
            .addFilter(new JwtEmailAndPasswordAuthenticationFilter(authenticationManager(), jwtConfig, secretKey))
            .addFilterAfter(new JwtTokenVerifier(secretKey, jwtConfig),JwtEmailAndPasswordAuthenticationFilter.class)
            .authorizeRequests()
            .anyRequest()
            .authenticated();
}

现在我需要创建一个每个人都可以访问的 Web 服务。为此，我添加了这一行：

.and().authorizeRequests().antMatchers("/auth/reset").permitAll()

链接文件管理器，它看起来像这样：

@Override
protected void configure(HttpSecurity http) throws Exception {
    http
            .cors().and()
            .csrf().disable()
            .sessionManagement()
            .sessionCreationPolicy(SessionCreationPolicy.STATELESS)
            .and()
            .addFilter(new JwtEmailAndPasswordAuthenticationFilter(authenticationManager(), jwtConfig, secretKey))
            .addFilterAfter(new JwtTokenVerifier(secretKey, jwtConfig),JwtEmailAndPasswordAuthenticationFilter.class)
            .authorizeRequests()
            .and().authorizeRequests().antMatchers("/auth/reset").permitAll()
            .anyRequest()
            .authenticated();
}

添加上面的行后我得到异常 JWT not found，它来自这个 JwtTokenVerifier bean，它被触发 addFilterAfter.

我的问题是，在请求不安全的 Web 服务时，如何防止触发 addFilterAfter 或仅安全路由所需的任何其他过滤器？

更新

这里是 JwtTokenVerifier bean 的定义：

public class JwtTokenVerifier extends OncePerRequestFilter {
    private final SecretKey secretKey;
    private final JwtConfig jwtConfig;

    public JwtTokenVerifier(SecretKey secretKey,
                            JwtConfig jwtConfig) {
        this.secretKey = secretKey;
        this.jwtConfig = jwtConfig;
    }

    @Override
    protected void doFilterInternal(HttpServletRequest request,
                                    HttpServletResponse response,
                                    FilterChain filterChain) throws ServletException, IOException {

        try {
            
            String authorizationHeader = request.getHeader(jwtConfig.getAuthorizationHeader());

            if (Strings.isNullOrEmpty(authorizationHeader) || !authorizationHeader.startsWith(jwtConfig.getTokenPrefix())) {
                filterChain.doFilter(request, response);
                return;
            }

            String token = authorizationHeader.replace(jwtConfig.getTokenPrefix(), "");

            try {

                Jws<Claims> claimsJws = Jwts.parser()
                        .setSigningKey(secretKey)
                        .parseClaimsJws(token);

                Claims body = claimsJws.getBody();

                String email = body.getSubject();

                var authorities = (List<Map<String, String>>) body.get("authorities");

                Set<SimpleGrantedAuthority> simpleGrantedAuthorities = authorities.stream()
                        .map(m -> new SimpleGrantedAuthority(m.get("authority")))
                        .collect(Collectors.toSet());

                Authentication authentication = new UsernamePasswordAuthenticationToken(
                        email,
                        null,
                        simpleGrantedAuthorities
                );

                SecurityContextHolder.getContext().setAuthentication(authentication);

            } catch (JwtException e) {
                throw new IllegalStateException(String.format("Token %s cannot be trusted", token));
            }

            filterChain.doFilter(request, response);
        } catch (JwtException e) {
        throw e;
    }
  }
}

Answer 1

你试过类似的东西吗:

      .and()
            .authorizeRequests()
            .antMatchers("...").permitAll()

        .and()
            .addFilter(...)
            .authorizeRequests()
            .anyRequest()
            .authenticated()
        .and()

Answer 2

我知道你没有问这个，但我首先建议你使用 Spring 安全的 built-in JWT support 而不是构建你自己的。安全很难，使用经过审查的支持可能更安全。

关于您关于为单独的端点使用单独的身份验证机制的问题，您可以改为发布两个过滤器链，一个用于开放端点，一个用于 token-based 个端点，如下所示：

@Bean
@Order(0)
SecurityFilterChain open(HttpSecurity http) {
    http
        .requestMatchers((requests) -> requests.antMatchers("/auth/reset"))
        .authorizeHttpRequests((authorize) -> authorize.anyRequest().permitAll());

    return http.build();
}

@Bean
SecurityFilterChain tokenBased(HttpSecurity http) {
    http
        .authorizeHttpRequests((authorize) -> authorize.anyRequest().authenticated())
        .addFilter(...)
        .addFilterAfter(...);

    return http.build();
}

尝试访问不安全的路由时出错

Gettig error while trying to access unsecured route

java

authentication

spring

spring-security

spring-boot