如何分别计算单个类别的列的总和？

Question

我需要一些帮助

我需要计算每位员工的总小时数，并在同一个 table.

中显示每位员工的所有日期

我的Table如下-

Employee	Date	hours
Rohit	06-03-2022	9
Rohit	07-03-2022	8
Rohit	08-03-2022	9
Rohit	09-03-2022	9
Rohit	10-03-2022	10
Rohit	11-03-2022	8
Rohit	12-03-2022	8
Rohit	06-03-2022	7
Raj	07-03-2022	8
Raj	08-03-2022	4
Raj	09-03-2022	3
Raj	10-03-2022	5
Raj	11-03-2022	8
Raj	12-03-2022	8

输出应该是这样的

Employee	Date	hours
Rohit	06-03-2022	9
Rohit	07-03-2022	8
Rohit	08-03-2022	9
Rohit	09-03-2022	9
Rohit	10-03-2022	10
Rohit	11-03-2022	8
Rohit	12-03-2022	8
Rohit	06-03-2022	7
Total		68
Raj	07-03-2022	8
Raj	08-03-2022	4
Raj	09-03-2022	3
Raj	10-03-2022	5
Raj	11-03-2022	8
Raj	12-03-2022	8
Total		36

Answer 1

你可以使用 GROUPING SETS 这个

SELECT
  Employee = CASE WHEN GROUPING(t.Date) = 0 THEN t.Employee ELSE 'Total' END,
  t.Date,
  hours = SUM(t.hours)
FROM YourTable t
GROUP BY GROUPING SETS (
    (Employee, Date),
    (Employee)
);

db<>fiddle

The GROUPING() function tells you whether a column has been aggregated for that row

如何分别计算单个类别的列的总和？

How to calculate the sum of a column by individual category separately?

sql

sql-server

sql-server-2012