创建嵌套子字典 python

Question

我在列表中有一些不同类型的学生姓名和每种类型的分数。例如：

students_exam_names = [exam_name1, exam_name2, exam_name3]
students_exam_score = [exam_score1, exam_score2, exam_score3]
students_quiz_names = [quiz_name1, quiz_name2]
students_quiz_score = [quiz_score1, quiz_score2]
students_homework_names = [homework_name1, homework_name2, homework_name3, homework_name4]
students_homework_score = [homework_score1, homework_score2, homework_score3, homework_score4]

所有三个都类似，如下所示。

我想以嵌套字典的形式获取详细信息，如下所示：

details = {'students_exam':{
    'exam_name1':exam_score1,
    'exam_name2':exam_score2,
    'exam_name3':exam_score3
},
'students_quiz':{
    'quiz_name1': quiz_score1,
    'quiz_name2': quiz_score2
},
'students_homework':{
    'homework_name1': homework_score1,
    'homework_name2': homework_score2,
    'homework_name3': homework_score3,
    'homework_name4': homework_score4,
}

每个学生类型的长度是不同的。我试图以如下词典列表的形式获取它，但无法更进一步。

students_exam = {}

for i in range(len(students_exam_names)):
  students_exam[students_exam_names[i]] = students_exam_score[i]

Answer 1

那么如果我假设你的完整输入集是这样的呢

students_exam_names = ['name1', 'name2', 'name3']
students_exam_score = ['score1', 'score2', 'score3']
students_quiz_names = ['name1', 'name2']
students_quiz_score = ['score1', 'score2']
students_homework_names = ['name1', 'name2', 'name3', 'name4']
students_homework_score = ['score1', 'score2', 'score3', 'score4']

如果是这样，那么下面的代码应该可以完成这项工作。

details={}
details['students_exam']={sexam: students_exam_score[students_exam_names.index(sexam)] for sexam in students_exam_names}
details['students_quiz']={squiz: students_quiz_score[students_quiz_names.index(squiz)] for squiz in students_quiz_names}
details['students_homework']={shome: students_homework_score[students_homework_names.index(shome)] for shome in students_homework_names}

Answer 2

您似乎需要一些函数来执行这些更新：

def update_exam(details, names, scores):
    results = {}
    for name,score in zip(names,scores):
        results[name]=score
    details['students_exam'] = results

def update_quiz(details, names, scores):
    results = {}
    for name,score in zip(names,scores):
        results[name]=score
    details['students_quiz'] = results

def update_homework(details, names, scores):
    results = {}
    for name,score in zip(names,scores):
        results[name]=score
    details['students_homework'] = results

details = {}
update_exam(details, students_exam_names, students_exam_score)
update_quiz(details, students_quiz_names, students_quiz_score)
update_homework(details, students_homework_names, students_homework_score)

但由于上述函数仅在键的文本名称上真正不同，因此可以进一步折叠它们：

def update(details, key, names, scores):
    results = {}
    for name,score in zip(names,scores):
        results[name]=score
    details[key] = results

details = {}

update(details,'students_exam', students_exam_names, students_exam_score)
update(details,'students_quiz', students_quiz_names, students_quiz_score)
update(details,'students_homework', students_homework_names, students_homework_score)

然后循环就可以变成字典推导了：

def update(details, key, names, scores):
    details[key] = {name:score for (name,score) in zip(names,scores)}

Answer 3

不要忘记在定义输入时使用 '：

students_exam_names = ['exam_name1', 'exam_name2', 'exam_name3']
students_exam_score = ['exam_score1', 'exam_score2', 'exam_score3']
students_quiz_names = ['quiz_name1', 'quiz_name2']
students_quiz_score = ['quiz_score1', 'quiz_score2']
students_homework_names = ['homework_name1', 'homework_name2', 'homework_name3', 'homework_name4']
students_homework_score = ['homework_score1', 'homework_score2', 'homework_score3', 'homework_score4']

然后，简单地使用压缩功能：

details = {'students_exam': dict(zip(students_exam_names, students_exam_score)),
           'students_quiz': dict(zip(students_quiz_names, students_quiz_score)),
           'students_homework': dict(zip(students_homework_names, students_homework_score))}

输出为：

{'students_exam': {'exam_name1': 'exam_score1', 'exam_name2': 'exam_score2', 'exam_name3': 'exam_score3'}, 'students_quiz': {'quiz_name1': 'quiz_score1', 'quiz_name2': 'quiz_score2'}, 'students_homework': {'homework_name1': 'homework_score1', 'homework_name2': 'homework_score2', 'homework_name3': 'homework_score3', 'homework_name4': 'homework_score4'}}

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