如何计算一列SQL的总和？

Question

需要一些帮助。

我的Table如下->

Project_Name	Date	Recorded_Hours	Planned_Hours	Remaining_Hours
Civil	06-03-2022	5	10	5
Civil	07-03-2022	3	7	4
Civil	08-03-2022	9	9	0
Civil	09-03-2022	4	10	6
Civil	10-03-2022	8	5	-3
Civil	11-03-2022	8	8	0
Civil	12-03-2022	0	5	-5
Civil	13-03-2022	0	4	-4
Civil	14-03-2022	0	3	-3
Civil	15-03-2022	0	4	-4
Civil	15-03-2022	0	5	-5

这里我只有一个项目，但实时我有多个项目。

In this table Recorded_Hours is total hours done per day, Planned_Hours is total hours planned per day and Remaining_Hours is ( Planned_Hours - Recorded_Hours ). I want to sum all the Remaining_Hours till today then distribute that sum evenly to each future Planned_Hours.

In this above table total sum of Remaining_Hours till today is 12 and there is 5 Days left to complete this project. I want to add 12/5 to each 5 Days left Planned_Hours. This should automatically calculate everyday.

我的输出将是 ->

Project_Name	Date	Recorded_Hours	Planned_Hours	Remaining_Hours
Civil	06-03-2022	5	10	5
Civil	07-03-2022	3	7	4
Civil	08-03-2022	9	9	0
Civil	09-03-2022	4	10	6
Civil	10-03-2022	8	5	-3
Civil	11-03-2022	8	8	0
Civil	12-03-2022	0	7.4	-7.4
Civil	13-03-2022	0	6.4	-6.4
Civil	14-03-2022	0	5.4	-5.4
Civil	15-03-2022	0	6.4	-6.4
Civil	15-03-2022	0	7.4	-7.4

到此为止

SELECT 
 [Project_Name]= CASE WHEN GROUPING(Date) = 0 THEN [Project_Name]ELSE 'Total' END,
  Date,
  [Remaining_Hours] = SUM([Planned_Hours]-[Recorded_Hours])
FROM[dbo].[Projects]

GROUP BY GROUPING SETS (
    ([Project_Name], Date),
    ([Project_Name]));

Answer 1

首先，您找到每个项目截至今天的总剩余小时数 (GROUP BY)

select Project, Total_Remaining_Hours = sum(Remaining_Hours),
from   Projects
where  [Date] <= @today 
group by Project

那你还需要剩余天数

select Project, Remaining_Days = count(*)
from   Projects
where  [Date] > @today 
group by Project

将它们组合在一起（INNER JOIN）并使用 CASE 表达式来检查，忽略过去的日期，只调整未来的日期

declare @today date = getdate();

select *,
       New_Planned_Hours = case when p.[Date] <= @today
                                then p.Planned_Hours
                                else p.Planned_Hours 
                                +    (t.Total_Remaining_Hours / d.Remaining_Days)
                                end
from   Projects p
       inner join
       (
          select Project,
                 Total_Remaining_Hours = sum(Remaining_Hours)
          from   Projects
          where  [Date] <= @today
          group by Project
       ) t  on p.Project = t.Project
       inner join
       (
          select Project,
                 Remaining_Days = count(*)
          from   Projects
          where  [Date] > @today
          group by Project
       ) d  on p.Project = d.Project
order by p.Project, p.[Date]

db<>fiddle demo

如何计算一列SQL的总和？

How to calculate the sum of a column SQL?

sql

sql-server-2012