“.service”中构造函数的参数 0 需要找不到类型为“.model”的 bean

Question

我正在创建一个 spring 引导应用程序，它用于过滤坏词。在任何客户端都可以提交请求的地方，这些请求可以是GET,POST

但是在创建此应用程序时，出现以下错误：

我的应用程序的结构是：

Model.WordFilter

package com.Website.Step2.model;
import lombok.AllArgsConstructor;
import lombok.Data;
import lombok.NoArgsConstructor;
import javax.persistence.*;
import javax.validation.constraints.NotBlank;
import static javax.persistence.FetchType.LAZY;
import static javax.persistence.GenerationType.IDENTITY;

@Data
@AllArgsConstructor
@NoArgsConstructor
@Entity
public class WordFilter {
    @Id
    @GeneratedValue(strategy = IDENTITY)
    private Long Id;
    @NotBlank(message = "Word is required")
    private String name;
    @ManyToOne(fetch = LAZY)
    private User user;
}

WordFilterService

package com.Website.Step2.service;
import com.Website.Step2.dto.WordFilterDto;
import com.Website.Step2.mapper.WordFiterMapper;
import com.Website.Step2.model.WordFilter;
import com.Website.Step2.repository.WordFilterRepository;
import lombok.AllArgsConstructor;
import org.springframework.stereotype.Service;
import org.springframework.transaction.annotation.Transactional;
import java.util.List;
import static java.util.stream.Collectors.toList;
@Service
@AllArgsConstructor

public class WordFilterService {
    private final WordFilterRepository wordFilterRepository;
    private final WordFiterMapper wordFiterMapper;
    private final AuthService authService;
    public WordFilterDto save(WordFilterDto wordFilterDto) {
        WordFilter save = wordFilterRepository.save(wordFiterMapper.mapDtoToWordFilter(wordFilterDto, authService.getCurrentUser()));
        wordFilterDto.setId(save.getId());
        return wordFilterDto;
    }
    @Transactional(readOnly = true)
    public List<WordFilterDto> getAll() {
        return wordFilterRepository.findAll()
                .stream()
                .map(wordFiterMapper::mapWordFilterToDto)
                .collect(toList());
    }
}

我知道已经有人问过很多有以下错误的问题，但我仍然无法解决这个问题。

Answer 1

问题已解决。我刚刚将所有 WordFilter 复制到另一个文件夹并删除了所有 WordFilter.And 我再次粘贴它。并且有效。

“.service”中构造函数的参数 0 需要找不到类型为“.model”的 bean

Parameter 0 of constructor in '.service ' required a bean of type '.model ' that could not be found

java

spring

spring-boot