文本解密程序没有给出正确的结果

Question

当您加密文本时，它可以正常工作，但是当您尝试在其中解密时，会出现奇怪的结果。我的代码正在运行，但突然崩溃了。问题是我不知道加密部分或解密部分是否损坏我将不胜感激。


abc = 'a b c d e f g h i j k l m n o p q r s t u v w x y z'
code = '! @ # $ % ^ & * ( ) _ + § ± , . / < > ? | ` ~ [ ] {'
code2 = '{ ] [ ~ ` | ? > < / . , ± § + _ ) ( * & ^ % $ # @ !'


while True:
    print()
    print('--------------')
    print('[1] text -> code\n[2] code -> text')
    print('--------------')
    inp = input('==> ')

# encrypting chosen
    if inp == '1':
        print('--------------')
        print('enter the text')
        print('--------------')
        inp = input('==> ')
        print('-----code-----')
        # for every character in the text given this runs
        for i in inp:
            # gets a random number between 1 and 2 because there is two diffirent alpabets
            # every letter will be cyrpted depending on a random alpabet
            rand = random.randint(1, 2)
            # gets the index for the character in abc
            ind = abc.index(i)
            if rand == 1:
                # prints the index in code2(1th alpabet) and adds '∑' so program know it belongs to 1th alpabet
                print(code2[ind], '∑', sep='', end='')
            elif rand == 2:
                # prints the index in code(@th alpabet) and adds '¥' so program know it belongs to 1th alpabet
                print(code[ind], '¥', sep='', end='')
# decrypting chosen
    elif inp == '2':
        print()
        print('--------------')
        print('enter the code')
        print('--------------')
        inp = input('==> ')
        print('-----text-----')
        # for every character in the text given this runs
        for i in inp:
            # checks the character next to the actual character if it is '∑'
            # to know which alpabet it belongs to
            if inp[inp.index(i)+1] == '∑':
                # gets the index and print the same index in abc
                ind = code2.index(i)
                print(abc[ind], end='')

            elif inp[inp.index(i)+1] == '¥':
                ind = code.index(i)
                print(abc[ind], end='')

    else:
        pass

Answer 1

这就是你想要的。请注意，我在编码字符之前添加了您的字母表移位。这样，当遍历编码文本时，我可以设置正确的解码字母表。

import random

abc  ='abcdefghijklmnopqrstuvwxyz'
code ='!@#$%^&*()_+§±,./<>?|`~[]{'
code2='{][~`|?></.,±§+_)(*&^%$#@!'

while True:
    print('\n--------------')
    print('[1] text -> code\n[2] code -> text')
    print('--------------')
    inp = input('==> ')

# encrypting chosen
    if inp == '1':
        print('--------------')
        print('enter the text')
        print('--------------')
        inp = input('==> ')
        print('-----code-----')
        # for every character in the text given this runs
        for i in inp:
            # gets a random number between 1 and 2 because there is two diffirent alpabets
            # every letter will be cyrpted depending on a random alpabet
            rand = random.randint(1, 2)
            # gets the index for the character in abc
            ind = abc.index(i)
            if rand == 1:
                # prints the index in code2(1th alpabet) and adds '∑' so program know it belongs to 1th alpabet
                print('∑', code2[ind], sep='', end='')
            elif rand == 2:
                # prints the index in code(@th alpabet) and adds '¥' so program know it belongs to 1th alpabet
                print('¥', code[ind], sep='', end='')
# decrypting chosen
    elif inp == '2':
        print()
        print('--------------')
        print('enter the code')
        print('--------------')
        inp = input('==> ')
        print('-----text-----')
        # for every character in the text given this runs
        which = code
        for i in inp:
            if i == '∑':
                which = code2
            elif i == '¥':
                which = code
            else:
                ind = which.index(i)
                print(abc[ind], end='')

更好的设计应该有一个 encode 函数和一个 return 字符串的 decode 函数，从而允许调用者决定如何处理这些字符串。

文本解密程序没有给出正确的结果

text crypter program dosent give right results

python

encryption