如何基于 N 个数组创建嵌套 while 循环?
How to create a nested while loop based on N number of arrays?
我正在尝试创建下面给出的数组的所有可能变体的组合,这些变体非常不言自明。
let arr1 = ['Small', 'Medium', 'Large', 'Extra-Large']
let arr2 = ['Black','Red','White']
let arr3 = ['Normal','Limited-Edition']
let combos = []
arr1.forEach((i) => {
arr2.forEach((j) => {
arr3.forEach((k) => {
combos.push(i + '-' + j + '-' + k)
})
})
})
console.log(combos)
这给出了我想要的输出,但是我想创建一个函数,该函数接受任意数组 [arr1, arr2, arr3.....arrN] 并为每个数组创建一个嵌套循环,和 returns 字符串的组合值。
如何创建这样的函数?
您可以通过 reduce
使用类似的东西。我引用了 this post
let arr1 = ['Small', 'Medium', 'Large', 'Extra-Large']
let arr2 = ['Black','Red','White']
let arr3 = ['Normal','Limited-Edition']
let arr4 = ['x','y','z']
let arr = [arr1,arr2,arr3,arr4]
let combined = arr.reduce((a,c)=>{
return a.flatMap(x=>c.map(y=>x.concat(y)))
},[[]]).map((z) => z.join("-"))
console.log(combined)
console.log(combined.length) //4*3*2*3 = 72
UPDATE - 这个直接取自最上面的答案,做了非常小的修改
let arr1 = ['Small', 'Medium', 'Large', 'Extra-Large']
let arr2 = ['Black','Red','White']
let arr3 = ['Normal','Limited-Edition']
let arr4 = ['x','y','z']
let arr = [arr1,arr2,arr3,arr4]
const cartesian =
(a) => a.reduce((a, b) => a.flatMap(d => b.map(e => [d, e].flat()))).map(x=>x.join("-"));
console.log(cartesian(arr))
const arr1 = ['Small', 'Medium', 'Large', 'Extra-Large']
const arr2 = ['Black','Red','White']
const arr3 = ['Normal','Limited-Edition']
const arr4 = ['x','y','z']
const arr = [arr1,arr2,arr3,arr4]
const merged = [].concat.apply([], arr);
console.log(merged);
我正在尝试创建下面给出的数组的所有可能变体的组合,这些变体非常不言自明。
let arr1 = ['Small', 'Medium', 'Large', 'Extra-Large']
let arr2 = ['Black','Red','White']
let arr3 = ['Normal','Limited-Edition']
let combos = []
arr1.forEach((i) => {
arr2.forEach((j) => {
arr3.forEach((k) => {
combos.push(i + '-' + j + '-' + k)
})
})
})
console.log(combos)
这给出了我想要的输出,但是我想创建一个函数,该函数接受任意数组 [arr1, arr2, arr3.....arrN] 并为每个数组创建一个嵌套循环,和 returns 字符串的组合值。
如何创建这样的函数?
您可以通过 reduce
使用类似的东西。我引用了 this post
let arr1 = ['Small', 'Medium', 'Large', 'Extra-Large']
let arr2 = ['Black','Red','White']
let arr3 = ['Normal','Limited-Edition']
let arr4 = ['x','y','z']
let arr = [arr1,arr2,arr3,arr4]
let combined = arr.reduce((a,c)=>{
return a.flatMap(x=>c.map(y=>x.concat(y)))
},[[]]).map((z) => z.join("-"))
console.log(combined)
console.log(combined.length) //4*3*2*3 = 72
UPDATE - 这个直接取自最上面的答案,做了非常小的修改
let arr1 = ['Small', 'Medium', 'Large', 'Extra-Large']
let arr2 = ['Black','Red','White']
let arr3 = ['Normal','Limited-Edition']
let arr4 = ['x','y','z']
let arr = [arr1,arr2,arr3,arr4]
const cartesian =
(a) => a.reduce((a, b) => a.flatMap(d => b.map(e => [d, e].flat()))).map(x=>x.join("-"));
console.log(cartesian(arr))
const arr1 = ['Small', 'Medium', 'Large', 'Extra-Large']
const arr2 = ['Black','Red','White']
const arr3 = ['Normal','Limited-Edition']
const arr4 = ['x','y','z']
const arr = [arr1,arr2,arr3,arr4]
const merged = [].concat.apply([], arr);
console.log(merged);