Lua 添加脚本中的索引无法正常工作

Question

我在 lua 中有此代码（如果不好，请见谅）。

function splitIntoTable(inputstr,sep)
  local t = {}
  for str in string.gmatch(inputstr,"([^" .. sep .. "]+)") do
    table.insert(t,str)
  end
  return t
end

function displayList(table)
  for k, v in ipairs(table) do
    print(table[k])
  end
end

local tocalc = "57 + 38"

print("Inputted: " .. tocalc)
tocalc = "0 " .. tocalc
local workwith = splitIntoTable(tocalc," ")
local did = 0
local doing = 1
local lenOfWorkwith = 0

for k in pairs(workwith) do
  lenOfWorkwith = lenOfWorkwith + 1
end

repeat
  if workwith[doing] == "+" then
    did = did + workwith[doing - 1] + workwith[doing + 1]
  end
  doing = doing + 1
until doing > lenOfWorkwith

did = math.floor(did + 0.5)

print("Result: " .. did)

我知道它有点低效，但我只需要它现在可用。基本上，它应该做的只是加数字。例如，我输入 57 + 38，它工作正常并给出正确的计算，但是一旦我输入 3 个数字（例如，57 + 38 + 40），它就会崩溃并且不给出正确答案。

Answer 1

根据您的 Lua 版本，您可以使用 load 或 loadstring 来显着简化此操作。

local tocalc = "57 + 38 + 40"
print("Result: " .. load("return " .. tocalc)())

您的算法正在额外添加中间项。

  if workwith[doing] == "+" then
    did = did + workwith[doing - 1] + workwith[doing + 1]
  end

这里第一个“+”是 did + 57 + 38，did 是 95。下一个“+”是 did + 38 + 40，所以要将 38 添加到最终值两次。要解决此问题，您只需查看数字并将它们单独相加，而不是成对相加。

repeat
  if workwith[doing] ~= "+" then
    did = did + workwith[doing]
  end
  doing = doing + 1
until doing > lenOfWorkwith

该算法还有其他问题，我强烈建议使用我上面描述的使用负载的解决方案。

Lua 添加脚本中的索引无法正常工作

Lua indexes in adding script doesn't work properly

math

lua

numbers