如何使用 Laravel 的查询生成器按状态过滤帖子？

Question

我正在开发一个包含用户和帖子的 Laravel 8 应用程序。

根据 posts table 中的所有条目，我需要制作 2 个帖子列表，具体取决于它们是 活跃的 还是待定。状态来自 post_statuses table，列 id 和 status.

在 Post 模型中我有：

class Post extends Model {
    use HasFactory;
    
    protected $fillable = [
        'title',
        'category_id',
        'description',
        'body'
        'status'
    ];
}

在控制器中：

namespace App\Http\Controllers;
use Illuminate\Http\Request;
use App\Models\Post;

class PostsController extends Controller {

    public $page_title = "Posts";

    public function index(Request $request) {
        $viewData = $this->loadViewData();
        $viewData['page_title'] = $this->page_title;
        $viewData['posts'] = $this->posts($request);
        // send active posts to the view
        return view('active_posts', $viewData);
    }

    public function posts(Request $request) {

            $query = $request->input('query');

            return Post::select (
                "posts.title",
                "posts.description",
                "posts.body",
                "categories.name as category_name",
                "post_statuses.status as post_status",
            )
            ->leftJoin("categories", "posts.category_id", "=", "categories.id")
            ->leftJoin("post_statuses", "posts.status", "=", "post_statuses.id")
            // filter by status
            ->where('post_statuses.status', '=', 'active')
            ->orWhere('title', 'like', '%' . $query . '%')
            ->orWhere('description', 'like', '%' . $query . '%')
            ->orWhere('body', 'like', '%' . $query . '%')
            ->orWhere('categories.name', 'like', '%' . $query . '%')
            ->orWhere('post_statuses.status', 'like', '%' . $query . '%')
            ->orderBy('posts.id','DESC')
            ->paginate(10);
    }
}

问题

在 active_posts 视图中，显示所有帖子，无论其状态如何。

我的错误在哪里？

Answer 1

我猜 orWhere 弄乱了你的查询。

这样试试：

public function posts(Request $request) {

    $query = $request->input('query');

    return Post::select (
        "posts.title",
        "posts.description",
        "posts.body",
        "categories.name as category_name",
        "post_statuses.status as post_status",
        )
        ->leftJoin("categories", "posts.category_id", "=", "categories.id")
        ->leftJoin("post_statuses", "posts.status", "=", "post_statuses.id")
        // filter by status
        ->where('post_statuses.status', '=', 'active')
        ->where(function ($q) use($query){
            $q->where('title', 'like', '%' . $query . '%')
                ->orWhere('description', 'like', '%' . $query . '%')
                ->orWhere('body', 'like', '%' . $query . '%')
                ->orWhere('categories.name', 'like', '%' . $query . '%')
                ->orWhere('post_statuses.status', 'like', '%' . $query . '%');
        })
        ->orderBy('posts.id','DESC')
        ->paginate(10);
}

如何使用 Laravel 的查询生成器按状态过滤帖子？

How can I filter posts by status with Laravel's query builder?

php

laravel

laravel-8

问题

我的错误在哪里？