在 java 中尝试线性搜索，但循环似乎没有迭代

Question

我正在尝试使用 java 的线性搜索来查找二维数组中的名称并打印与其相关的详细信息，但是代码直接进入最后一个循环而没有搜索

密码是

import java.io.*;
import java.util.*;
import java.text.*;
import java.math.*;
import java.util.regex.*;

public class Source {

String customerDetails[][]=new String[5][3];
Source()
{
customerDetails[0][0]="1001";
customerDetails[0][1]="Raj";
customerDetails[0][2]="Chennai";

customerDetails[1][0]="1008";
customerDetails[1][1]="Akshay";
customerDetails[1][0]="Pune";

customerDetails[2][0]="1002";
customerDetails[2][1]="Simrath";
customerDetails[2][2]="Amristar";

customerDetails[3][0]="1204";
customerDetails[3][1]="Gaurav";
customerDetails[3][2]="Delhi";

customerDetails[4][0]="1005";
customerDetails[4][1]="Ganesh";
customerDetails[4][2]="Chennai";

}

public static void main(String args[] ) throws Exception {
    
    Source nc = new Source();
    Scanner sc = new Scanner(System.in);
    String key = sc.nextLine();
    boolean found = false;
    for(int i=0;i<5;i++){
        for(int j=0;j<3;j++){
            
            if(nc.customerDetails[i][j].equals(key)){
                found = true;
                System.out.println(nc.customerDetails[i][0] + '\n' + nc.customerDetails[i][1] + '\n' + nc.customerDetails[i][2]);
                break;
                
            }
        }
        if(!found){
            System.out.println("No Record Found");
            break;
        }
    }
}
}

我想在数组中找到 Gaurav 并打印 1204 高拉夫德里

Answer 1

public class test
{

    String customerDetails[][] = new String[5][3];

    test()
    {
        customerDetails[0][0] = "1001";
        customerDetails[0][1] = "Raj";
        customerDetails[0][2] = "Chennai";

        customerDetails[1][0] = "1008";
        customerDetails[1][1] = "Akshay";
        customerDetails[1][2] = "Pune";

        customerDetails[2][0] = "1002";
        customerDetails[2][1] = "Simrath";
        customerDetails[2][2] = "Amristar";

        customerDetails[3][0] = "1204";
        customerDetails[3][1] = "Gaurav";
        customerDetails[3][2] = "Delhi";

        customerDetails[4][0] = "1005";
        customerDetails[4][1] = "Ganesh";
        customerDetails[4][2] = "Chennai";

    }

    public static void main(String args[]) throws Exception
    {

        test nc = new test();
        Scanner sc = new Scanner(System.in);
        String key = sc.nextLine();
        boolean found = false;
        for (int i = 0; i < 5; i++)
        {
            for (int j = 0; j < 3; j++)
            {

                if (nc.customerDetails[i][j].equals(key))
                {
                    found = true;
                    System.out.println(nc.customerDetails[i][0] + '\n' + nc.customerDetails[i][1] + '\n' + nc.customerDetails[i][2]);
                    break;

                }
            }

        }
        if (!found)
        {
            System.out.println("No Record Found");
            // break;
        }
    }
}

这应该有效。 if(!found) 应该在循环外检查所有记录。

在 java 中尝试线性搜索，但循环似乎没有迭代

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