iOS / Swift - 无法在 Init() 上设置枚举值

Question

我创建了 SKSpriteNode 的扩展 class。我正在制作砖块对象，当它们被击中时会有不同的行为

import SpriteKit

class Brick: SKSpriteNode {

    enum type {
        case None, Green, Yellow, Orange, Red
    }

    static let colorMap = [
        Brick.type.Green : UIColor.greenColor(),
        Brick.type.Yellow : UIColor.yellowColor(),
        Brick.type.Orange : UIColor.orangeColor(),
        Brick.type.Red : UIColor.redColor()
    ]

    var brickType = Brick.type.None

    convenience init (size: CGSize, type: Brick.type) {
        self.init(color: UIColor.whiteColor(), size: size)

        // Here I set the initial type and color
        // The color is assigned just fine, but the brickType
        // variable is still Brick.type.None
        self.setType(type)
    }

    func gotHit () -> Int {
        switch (self.brickType) {
            case Brick.type.Yellow:
                setType(Brick.type.Green);
                break;

            case Brick.type.Orange:
                setType(Brick.type.Yellow);
                break;

            case Brick.type.Red:
                setType(Brick.type.Orange);
                break;

            case Brick.type.Green: // Green
                self.removeFromParent()
                return 1

            default:
                break
        }

        return 0
    }

    func setType (typeToSet: Brick.type) {
        self.brickType = typeToSet // only works when called from gotHit()
        self.color = Brick.colorMap[typeToSet]! // this works everytime
    }
}

然后我创建一个实例 class:

let brickPrototype = Brick(size: CGSizeMake(55, 25), type: Brick.type.Green)

我的问题是，尽管在 convenience init () 中调用 setType()，public brickType 变量的值仍然是默认值，Brick.type.None.改色没有问题，看来参数传递正确

如果我将默认的 brickType 变量设置为 Brick.type.Yellow，并执行 gotHit() 函数，setType() 函数将有效地将砖块类型更改为 Brick.type.Green，再次调用后，通过调用 self.removeFromParent() 从视图中删除该节点。因此，我确定问题出在我从 convenience init() 调用函数时，即使我没有收到任何错误。

Answer 1

如果您是第一次在初始化程序中设置它，则不需要有默认值。尚未对此进行测试以查看它是否解决了您的问题，但我确实稍微清理了代码。

class Brick: SKSpriteNode {

enum BrickColorType: UInt {
    case Red
    case Orange
    case Yellow
    case Green //This order matters for nextColor

    func color() -> UIColor {
        switch self {
        case Green:
            return .greenColor() //Swift does not need break statements in cases.
        case Yellow:
            return .yellowColor()
        case Orange:
            return .orangeColor()
        case Red:
            return .redColor()
        }
    }

    func nextColor() -> BrickColorType? {
        return BrickColorType(rawValue: self.rawValue.successor()) //If self = green, this will return nil.
    }

}

var brickType: BrickColorType {
    didSet {
        self.color = brickType.color()
    }
}

init (size: CGSize, type: BrickColorType) {
    brickType = type
    super.init(texture: nil, color: .whiteColor(), size: size) //Because the earlier one was a convenience init and Xcode was complaining
    self.color = brickType.color() //Because didSet is not called in initializer
}

required init?(coder aDecoder: NSCoder) { //This is just boilerplate required to inherit from any NSObject
    brickType = .Red //Or whatever else. If you really want to add a None case to the enum, might I suggest instead making brickType optional?
    super.init(coder: aDecoder)
}

func gotHit () -> Int { //Consider making this a Bool

    if let next = self.brickType.nextColor() {
        //There is a valid next color
        brickType = next
        return 0
    }

    //There is no valid next color
    self.removeFromParent()
    return 1

}
} //Weird formatting because of Whosebug

iOS / Swift - 无法在 Init() 上设置枚举值

iOS / Swift - Unable to set Enum Value on Init()

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