函数的相反 return

Question

我正在做一些 Python 练习，由于某种原因，我的功能正在返回相反的 bool 值。如果函数下的语句需要“不”才能正常工作 - 谁能解释我做错了什么？

number = int(input("Enter numbers you want to check: "))


def dividers(number):
temp_tab = range(2, number)
divider = 0

for x in temp_tab:
    while number % x == 0:
        divider += 1
        if divider > 1:
            return False
        else:
            return True


if not dividers(number):
   print("It is a prime number")
else:
   print("It is not a prime number")

Answer 1

您似乎想要一个函数来检查数字是否为质数：

def is_prime(number):
    if number <= 1: return False

    for x in range(2, number):
        if number % x == 0:
            return False
    return True


number = int(input("Enter numbers you want to check: "))

if is_prime(number):
    print("It is a prime number")
else:
    print("It is not a prime number")