如何查找包含两个单词 "First" + "Second" 的行，而不考虑顺序？

Question

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如何查找包含两个单词“First”+“Second”的行，无论顺序与否？正在寻找一个 where 条件来涵盖这种情况。

这是我的表格：

---------------------------
RowNo, MyStringColumn
---------------------------
1 , 'First Second Third'
2 , 'Second Third First'
3 , 'Third First Second'
4 , 'First Third Second'
5 , 'Second Second Third'

预期结果：第 1、2、3、4 行

---------------------------
RowNo, MyStringColumn
---------------------------
1 , 'First Second Third'
2 , 'Second Third First'
3 , 'Third First Second'
4 , 'First Third Second'

低于 SQL return第 1、3、4 行并且 return 由于序列无序而不是第 2 行。

SELECT * FROM MyTable WHERE MyStringColumn like '%First%Second%

这里是SQL生成MyTable和数据的脚本

DROP TABLE IF EXISTS [#MyTable];
SELECT [RowNo],[MyStringColumn] INTO [#MyTable]
FROM (SELECT (1)[RowNo], ('First Second Third')[MyStringColumn]
       UNION SELECT 2, 'Second Third First'
       UNION SELECT 3, 'Third First Second'
       UNION SELECT 4, 'First Third Second'
       UNION SELECT 5, 'Second Second Third'
)t

SELECT * FROM [#MyTable] WHERE [MyStringColumn] LIKE '%First%Second%'

Answer 1

只需 LIKE 两次。

SELECT *
FROM MyTable
WHERE MyStringColumn LIKE '%First%' 
  AND MyStringColumn LIKE '%Second%'

如果您想确保它是 2 个单独的词

SELECT *
FROM MyTable
WHERE ' '+MyStringColumn+' ' LIKE '% First %' 
  AND ' '+MyStringColumn+' ' LIKE '% Second %'

Answer 2

string_split 基于方法。当你想检查很多单词时很有用：

select *
from t
where exists (
    select 1
    from string_split(t.MyStringColumn, ' ')
    where value in ('first', 'second')
    having count(distinct value) = 2 -- this should match the number of items in the "in" clause
)

如何查找包含两个单词 "First" + "Second" 的行，而不考虑顺序？

How do I find rows that contain two words "First" + "Second" regardless sequence?

sql

sql-server

sql-server-2019