使用矩阵加密文本

Question

[![скрин][1]][1][我需要让它看起来像屏幕上的样子，但我确定我做错了。关键是有一个字符串 str，在本例中是（我非常爱我妈妈，也很喜欢汽车），在矩阵中输入这个字符串后，您需要将它分成 5 个字母一组。结果应该如下(irlyo bvieg maynm dolto hveer cvaer).

public static void main(String[] args) {


        String[][] matrixA;
        matrixA = new String[2][15];

        matrixA[0][0] = "i";
        matrixA[0][1] = "l";
        matrixA[0][2] = "o";
        matrixA[0][3] = "v";
        matrixA[0][4] = "e";
        matrixA[0][5] = "m";
        matrixA[0][6] = "y";
        matrixA[0][7] = "m";
        matrixA[0][8] = "o";
        matrixA[0][9] = "t";
        matrixA[0][10] = "h";
        matrixA[0][11] = "e";
        matrixA[0][12] = "r";
        matrixA[0][13] = "v";
        matrixA[0][14] = "e";
        matrixA[1][0] = "r";
        matrixA[1][1] = "y";
        matrixA[1][2] = "b";
        matrixA[1][3] = "i";
        matrixA[1][4] = "g";
        matrixA[1][5] = "a";
        matrixA[1][6] = "n";
        matrixA[1][7] = "d";
        matrixA[1][8] = "l";
        matrixA[1][9] = "o";
        matrixA[1][10] = "v";
        matrixA[1][11] = "e";
        matrixA[1][12] = "c";
        matrixA[1][13] = "a";
        matrixA[1][14] = "r";


        for (int i = 0; i < matrixA.length; i++) {
            for (int j = 0; j < matrixA[i].length; j++) {
                System.out.print(matrixA[i][j] + "\t");
            }
            System.out.println();
        }
    }

Answer 1

我看到底部有两个 for-loops 在矩阵上循环。为了实现您要求的算法，我们需要做的就是遍历矩阵但翻转维度。然后使用模数检查是否是时候添加 space 了。试试这个功能吧，有问题可以私信我

public static String getGroups(String[][] matrix, int groupSize) {
    String output = "";
    int matrixWidth = matrix.length;
    int matrixHeight = matrix[0].length;
    
    int k = 0;
    for (int i = 0; i < matrixHeight; i++) {
        for (int j = 0; j < matrixWidth; j++) {
            k++;
            output += matrix[j][i];
            if(k % groupSize == 0) output += " ";
        }
    }
    
    return output;
}

您需要做的就是调用 getGroups，传入 matrixA 并传入 groupSize 为 5。这就是它的样子：System.out.println(getGroups(matrixA, 5));

另外请注意，您在此行 double-quotation 标记 (") matrixA[0][10] = h";

这意味着完整的代码应该如下所示：

public static void main(String[] args) {
    String[][] matrixA;
    matrixA = new String[2][15];

    matrixA[0][0] = "i";
    matrixA[0][1] = "l";
    matrixA[0][2] = "o";
    matrixA[0][3] = "v";
    matrixA[0][4] = "e";
    matrixA[0][5] = "m";
    matrixA[0][6] = "y";
    matrixA[0][7] = "m";
    matrixA[0][8] = "o";
    matrixA[0][9] = "t";
    matrixA[0][10] = "h";
    matrixA[0][11] = "e";
    matrixA[0][12] = "r";
    matrixA[0][13] = "v";
    matrixA[0][14] = "e";
    matrixA[1][0] = "r";
    matrixA[1][1] = "y";
    matrixA[1][2] = "b";
    matrixA[1][3] = "i";
    matrixA[1][4] = "g";
    matrixA[1][5] = "a";
    matrixA[1][6] = "n";
    matrixA[1][7] = "d";
    matrixA[1][8] = "l";
    matrixA[1][9] = "o";
    matrixA[1][10] = "v";
    matrixA[1][11] = "e";
    matrixA[1][12] = "c";
    matrixA[1][13] = "a";
    matrixA[1][14] = "r";

    for (int i = 0; i < matrixA.length; i++) {
        for (int j = 0; j < matrixA[i].length; j++) {
            System.out.print(matrixA[i][j] + "\t");
        }
        System.out.println();
    }
    
    System.out.println(getGroups(matrixA, 5));
}

public static String getGroups(String[][] matrix, int groupSize) {
    String output = "";
    int matrixWidth = matrix.length;
    int matrixHeight = matrix[0].length;
    
    int k = 0;
    for (int i = 0; i < matrixHeight; i++) {
        for (int j = 0; j < matrixWidth; j++) {
            k++;
            output += matrix[j][i];
            if(k % groupSize == 0) output += " ";
        }
    }
    
    return output;
}

Answer 2

@IvanKolisnik，要处理您指定的字符串：i love my mother very big and love car 并使用 getGroups() 提供的方法 @MorganS42 你需要做这样的事情：

创建矩阵（就像您展示的示例一样）

String strg = "i love my mother very big and love car";
strg = strg.replaceAll("\s+", ""); // Remove all whitespaces!
int columns = strg.length() / 2;
String[][] matrix = new String[2][columns];

int indexer = 0;
for (int row = 0; row < matrix.length; row++) {
    for (int column = 0; column < matrix[row].length; column++) {
        matrix[row][column] = Character.toString(strg.charAt(indexer));
        indexer++;
    }
}

// Display Current Generated Matrix...
for (int i = 0; i < matrix.length; i++) {
    for (int j = 0; j < matrix[i].length; j++) {
        if (matrix[i][j].isEmpty()) {
            break;
        }
        System.out.print(matrix[i][j]);
    }
    System.out.println();
}

System.out.println();

显示加密行（根据您的规格）：

/* Get the desired grouping from the generated 
   matrix and displsy it to console...     */
String encryptedString = getGroups(matrix, 5);
System.out.println(encryptedString);

到控制台的输出应该是:

ilovemymotherve
rybigandlovecar

irlyo bvieg maynm dolto hveer cvaer

因此...如果要加密的字符串是：

I love my mother very big but I love my car bigger!

控制台输出为：

Ilovemymotherverybig
butIlovemycarbigger!

Ibluo tvIel moyvm eomty hcear rvbei rgygb eirg!

使用矩阵加密文本

Encryption of text using a matrix

java

matrix