Bot 框架自定义操作和自定义 ArrayExpression 属性

Question

我正在使用 Microsoft 的 Bot Framework Composer 构建一个机器人。为了扩展 composer 的标准功能，我还构建了一些 Custom Actions，包括需要以特定类型的数组形式输入的操作。这是架构：

{
  "$schema": "https://schemas.botframework.com/schemas/component/v1.0/component.schema",
  "$role": "implements(Microsoft.IDialog)",
  "title": "AdvancePropertyTest",
  "description": "Test advanced properties in for custom actions.",
  "type": "object",
  "additionalProperties": false,
  "properties": {
    "skillSelectors": {
      "$ref": "schema:#/definitions/arrayExpression",
      "title": "SkillSelector Items",
      "description": "SkillSelector Items.",
      "items": {
        "title": "SkillSelector Item",
        "description": "SkillSelector Item.",
        "type": "object",
        "properties": {
          "key": {
            "title": "Key",
            "description": "The skill key to query against.",
            "type": "string"
          },
          "operator": {
            "title": "Operator",
            "description": "Describes how the value of the label is compared to the value defined on the label selector.",
            "type": "string",
            "enum": [
              "Equal",
              "NotEqual",
              "LessThan",
              "LessThanEqual",
              "GreaterThan",
              "GreaterThanEqual"
            ],
            "default": "Equal"
          },
          "value": {
            "title": "Value",
            "description": "The value to compare against the actual label value with the given operator.",
            "type": "integer"
          }
        }
      }
    }
  }
}

在作曲家中，结果是： Composer action with custom properties

到目前为止，还不错。现在，在对话框的代码中，为了检索输入数据，这就是我所做的：

[Serializable]
public class SkillSelector
{
    [JsonProperty(PropertyName = "key")]
    public string Key { get; set; }

    [JsonProperty(PropertyName = "operator")]
    public string Operator { get; set; }

    [JsonProperty(PropertyName = "value")]
    public int Value { get; set; }
}


public class AdvancedPropertyTest : Dialog
{
    [JsonProperty("skillSelectors")]
    public ArrayExpression<SkillSelector> SkillSelectors { get; set; }
    //public ArrayExpression<Metadata> SkillSelectors { get; set; }


    public override async Task<DialogTurnResult> BeginDialogAsync(DialogContext dc, object options = null, CancellationToken cancellationToken = default)
    {
        var skillSelectors = SkillSelectors?.GetValue(dc.State);
        // some code

        return await dc.EndDialogAsync(cancellationToken: cancellationToken);
    }
}

不幸的是，一旦我运行它会导致以下错误消息：

AdvancedProperties.dialog error: Cannot deserialize the current JSON array (e.g. [1,2,3]) into type ‘AdaptiveExpressions.Properties.ArrayExpression`1[SkillSelector]’ because the type requires a JSON object (e.g. {“name”:“value”}) to deserialize correctly.

To fix this error either change the JSON to a JSON object (e.g. {“name”:“value”}) or change the deserialized type to an array or a type that implements a collection interface (e.g. ICollection, IList) like List<T> that can be deserialized from a JSON array. JsonArrayAttribute can also be added to the type to force it to deserialize from a JSON array.

Path ‘skillSelectors’, line 49, position 37.

有趣的是，使用 class Microsoft.Bot.Builder.AI.QnA.MetaData 作为 ArrayExpression 中的通用类型就可以了，但是，当然，这不是我想要的。

有人知道如何做到这一点吗？任何帮助将不胜感激干杯。

Answer 1

您的属性应该来自 AdaptiveExpressions.Properties。因此，不要使用字符串 StringExpression、BoolExpression 等：

    [JsonProperty("businessUnitName")]
    public StringExpression BusinessUnitName { get; set; }

    [JsonProperty("reloadData")]
    public BoolExpression ReloadData { get; set; }

获取值：

BusinessUnitName.GetValue(dc.State)

Answer 2

好的，终于找到解决办法了。我在 BotComponent class 的 ConfigureServices 方法中添加了以下行：

public override void ConfigureServices(IServiceCollection services, IConfiguration configuration)
{
    services.AddSingleton<DeclarativeType>(sp => new DeclarativeType<AdvancedPropertyTest>(nameof(AdvancedPropertyTest)));
    services.AddSingleton<JsonConverterFactory, JsonConverterFactory<ArrayExpressionConverter<SkillSelector>>>();
}

这会在 JsonSerializer.

中添加 class SkillSelector

希望这对其他人有帮助。

Bot 框架自定义操作和自定义 ArrayExpression 属性

Bot Framework Custom Action and custom ArrayExpression property

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