如何在php循环中分别计算总数digit/numbers、奇数和偶数

Question

我想计算金字塔循环中的总数，我想分别计算所有的奇数和偶数。我的代码中存在错误计算奇数和偶数的问题。

结果应该是：

Total numbers:

Total odd numbers:

Total Even numbers:

<?php


if (isset($_POST['btnsend'])) {
$oddCount = 0;
$evenCount = 0;

$num = $_POST['number'];
$width = strlen($_POST['number']) + 1;
for ($row = 1; $row <= $num; $row++) {
    if ($ % 2 == 0) 
        $evenCount++;
    else
        $oddCount++;
    echo "<div style='display: flex; justify-content: center; text-align: center;'>";
    for ($x = 1; $x <= $row; $x++) {
        echo "<div style='width: {$width}ch; background: green;'>$row&nbsp;&nbsp;</div>";
    }
    echo "</div>";
}


echo "<p>You have {$evenCount} even and {$oddCount} odd numbers</p>";

}

Answer 1

我认为您应该能够自己解决这个问题。这不是一个难题。学习编程就是学习解决问题。如果你一直要求别人解决你的问题，你就不是在学习自己。

话虽这么说，我想你想要的是：

<?php

$userInput = 5;
$oddCount  = 0;
$evenCount = 0;

$num = $userInput;
$width = strlen($num) + 1;
for ($row = 1; $row <= $num; $row++) {
    if ($row % 2 == 0) {
        $evenCount += $row;
    } else {
        $oddCount += $row;
    }    
    echo "<div style='display: flex; justify-content: center; text-align: center;'>";
    for ($x = 1; $x <= $row; $x++) {
        echo "<div style='width: {$width}ch; background: green;'>$row&nbsp;&nbsp;</div>";
    }
    echo "</div>";
}

echo "<p>You have {$evenCount} even and {$oddCount} odd numbers</p>";

我不得不删除 $_POST 因为我没有你的表格。对于 5 这个 returns 的输入：

You have 6 even and 9 odd numbers

将输入更改为 10，您将得到：

You have 30 even and 25 odd numbers

如你所见，这并不难。

如何在php循环中分别计算总数digit/numbers、奇数和偶数

How to count the total digit/numbers, the odd numbers and even numbers respectively in a php loop

html

php

loops

count