python 要过滤的列表中的字典键 - python

Question

a = [{"price": 1,"id": 1},{"price": 8.2, "id": 2}, {"price": 10.99,"id": 3}]

user = ['price', 'abc']

输出应该是：

output = [{"price": 1},{"price": 8.2}, {"price": 10.99}]

场景是 dict a keys 应该被 user list

过滤

Answer 1

您可以使用列表理解

[{u: val_a.get(u) for u in user if val_a.get(u)} for val_a in a]

嵌套理解可能并不理想，上面的示例对值进行了两次检查。通过循环构建结果可能会给出最直接的结果并且同时可读：

results = []
for val_a in a:
    result = {}
    for u in user:
        u_val = val_a.get(u)
        if u_val:
            result.update({u: u_val})
    results.append(result)

Python3.8+:

results = []
for val_a in a:
    result = {}
    for u in user:
        if u_val := val_a.get(u)
            result.update({u: u_val})
    results.append(result)

Answer 2

您可以使用集合交集操作来获取要保留的键：

result = [{k: d[k] for k in set(d.keys()).intersection(set(user))} for d in a]
print(result)

这会打印：

[{'price': 1}, {'price': 8.2}, {'price': 10.99}]

python 要过滤的列表中的字典键 - python

python dict key in list to filter - python

python

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