读取成功 spotify 的响应 api post（创建播放列表）

Question

抱歉，我认为这是非常基本的，但我花了一段时间试图找到答案，但我无法解决。

我正在使用 spotify api / spotipy 来制作播放列表，它可以工作并且播放列表已创建，但我想检索 playlist_id 这样我就可以向其中添加曲目，但我不知道如何从 api.

获取任何响应信息

def make_playlist(name='python_play'):
    user = sp.me()['id']
    sp.user_playlist_create(user=user,name=name)
response = make_playlist()
pprint (response)

returns "None"

我以为我会调用 response.text 或 repsonse.contents 或类似的东西，但响应是 none 类型，我不能从中调用任何东西？

我一直很高兴地从 api 中检索信息，然后使用该信息通过 sqlalchemy 填充数据库，但我不明白在创建播放列表时如何实际获得响应。

api 成功调用 info/db 人口的示例：

def get_artists(num=1):
    '''takes num, retrieves num artists, returns list of dicts'''
    if num <=50:
        limit = num
    else:
        limit = 50
    artist_list = []
    after = 0
    for offset in range(0, num, 50):
        response = sp.current_user_followed_artists(limit=limit, after=after)
        for artist in response['artists']['items']:
            artist_name = artist['name']
            artist_id = artist['id']
            artist_dict={"artist name": artist_name,
                         "artist id": artist_id}
            artist_list.append(artist_dict)
            after = artist_id
    return artist_list


def new_artist(artist_list):
    '''takes list of artists, writes to db'''
    session = Session()
    artist_list = artist_list
    for artist in artist_list:
        new_artist = Artist(artist_name=artist['artist name'], artist_id=artist['artist id'])
        session.merge(new_artist)
        session.commit()
    session.close()


def populate_artists(num=1000):
    '''takes num_artists, calls get_artists, calls new_artist'''
    artist_list = get_artists(num)
    new_artist(artist_list)
    return artist_list


artist_list = populate_artists(10)

Answer 1

你实际上 return 根本不是你的 make_plalist() 函数中的任何东西。

Answer 2

我找到了一种通过播放列表名称搜索播放列表 ID 的解决方法，但我确定必须有一种方法可以在我创建播放列表时简单地对 ID 进行 Spotify return？

def GetPlaylistID(playlist_name):
    playlist_id = ''
    playlists = sp.current_user_playlists()
    for playlist in playlists['items']:  # iterate through playlists I follow
        if playlist['name'] == playlist_name:  # filter for newly created playlist
            playlist_id = playlist['id']
    return playlist_id


def make_playlist(playlist_name='python_play'):
    user = sp.me()['id']
    sp.user_playlist_create(user=user,name=playlist_name)
    playlist_id = GetPlaylistID(playlist_name)
    return playlist_id

Answer 3

@StayPerfect 的意思是，您忘记了 return 第 3 行中 sp.user_playlist_create() 的响应：

def make_playlist(name='python_play'):
    user = sp.me()['id']
    return sp.user_playlist_create(user=user,name=name)
response = make_playlist()
pprint (response)

读取成功 spotify 的响应 api post（创建播放列表）

read response from successful spotify api post (create playlist)

python

spotify

spotipy