我无法在 C++ 中用 'cout' 打印出句子

Question

首先我的母语不是英语，所以如果您发现我的英语有错误请忽略它们，

在我的代码下方

#include <iostream>
#include <string>
#include <vector>


using namespace std;
 
//Globle variables
 
int Counter = 0 ;
vector<string> tasksList;
string task;
 
//functions
 
int AddingTasks(){ 
    cout<<"type your task here: ";
    cin>>task;
    tasksList[Counter-1].assign(task); // the "Counter-1" to set the index to zero because 'Counter' variable = 1  
    cout<<tasksList[Counter-1]<<"added "<<endl; // the problem is here it crash here it won't print out this Sentence 
  return 0;
}

int main(int argc, char const *argv[])
{
      tasksList.resize(Counter);
      int ChooseNum;
      cout<<"Mustafa ToDoList the best to do list ever!  "<<endl;
      cout<<"Choose: [1] add task [2] view tasks [3] edit task [4] delete task : ";
      cin>>ChooseNum;
      if (ChooseNum == 1)
      {
        Counter++;
        AddingTasks();
      }
      // [2][3][4] are unnecessary now



   return 0;
}

我认为我的代码没有错误，但是 'AddingTasks()' 函数有问题程序在尝试打印已添加的任务时崩溃，我不知道为什么？

我是 C++ 初学者。

Answer 1

更改添加任务：

int AddingTasks()
{
    cout << "type your task here: ";
    cin >> task;
    tasksList.push_back(task);
    cout << tasksList[tasksList.size() - 1] << " added " << endl;
    return 0;
}

如果您尝试访问矢量中不存在的对象，会发生什么情况。

我无法在 C++ 中用 'cout' 打印出句子

I can't print out sentence with 'cout' in c++

c++

arrays

cout