按字母顺序从小到大对两个简单列表进行排序，然后将它们合并到字典中

Question

我有这些列表：

aList = ['a','d','n','e','z']
numList=[1,14,5,26,4]

输出应该是：

aDict = {'a':1, 'd':4, 'e':5, 'n':14, 'z':26}

我的代码是：

a = aList.sort()
b = bList.sort()

#merge both into a dict

Answer 1

尝试使用字典理解：

aDict = {key:value for key, value in zip(sorted(aList), sorted(numList))}
print(aDict)

输出：

{'a': 1, 'd': 4, 'e': 5, 'n': 14, 'z': 26}

Answer 2

鉴于： aList = ['a','d','n','e','z'] numList=[1,14,5,26,4]

首先对列表进行排序：aList.sort(),numList.sort()

然后压缩它们： aDict = dict(zip(aList,numList))

Sort two simple lists alphabetically and from least to greatest, then merge them into a dictionary