从结构数组接受数组

Question

我需要打印所有平均成绩大于或等于给定平均成绩的学生。

#include <stdio.h>
struct Student {
  char name[20], surname[20];
  int grades[50];
  int number_of_grades;
};
void print_average(struct Student students[], int n, double avarage) {
  double avarage_grade;
  int i;
  for (i = 0; i < n; i++) {
    avarage_grade =
        (double)(students[i].grades[i]) / students[i].number_of_grades;
    if (avarage_grade >= avarage)
      printf("%s %s\n", students[i].surname, students[i].name);
  }
}
int main() {
  struct Student students[] = {{"Meho", "Behic", {10, 9}, 2},
                               {"Meho", "Aehic", {10, 8}, 2},
                               {"Meho", "Cehic", {10, 9, 8, 7, 6}, 5},
                               {"Meho", "Dehic", {6, 9}, 2},
                               {"Meho", "Zehic", {10}, 1},
                               {"Meho", "Oehic", {10, 9, 9, 9}, 4}};
  print_average(students, 6, 9.2);
  return 0;
}

程序应该只打印两个学生。这不会打印任何内容，因为我在访问数组 grades 元素时犯了一个错误。你能帮我解决这个问题吗？

Answer 1

当您计算平均分时，您只需要单个成绩并将其除以成绩数。你需要先把成绩加起来。

void print_average(struct Student students[], int n, double avarage) {
  double avarage_grade;
  int i, j;
  for (i = 0; i < n; i++) {
    for (j=0, avarage_grade=0; j<students[i].number_of_grades; j++) {
        avarage_grade += students[i].grades[j];
    }
    avarage_grade /= students[i].number_of_grades;
    if (avarage_grade >= avarage)
      printf("%s %s\n", students[i].surname, students[i].name);
  }
}

从结构数组接受数组

Accept array from struct array

c

arrays

struct