安排云功能更新地图列表
Schedule cloud function to update a list of maps
我正在尝试编写一个预定的云函数来在每天凌晨 12 点重置“状态”的值。这是我的 Firestore 结构:
我以前没有真正尝试过在 javascript 中编码,但这是我用我的一点知识管理的:
const functions = require("firebase-functions");
const admin = require("firebase-admin");
admin.initializeApp();
const database = admin.firestore();
exports.Rst = functions.pubsub.schedule("0 0 * * *").onRun((context) => {
const alist =
database.collection("SA1XAoC2A7RYRBeAueuBL92TJEk1")
.doc("afternoon").get().then((snapshot)=>snapshot.data["list"]);
for (let i=0; i<alist.length; i++) {
alist[i]["status"]=0;
}
database.collection("SA1XAoC2A7RYRBeAueuBL92TJEk1")
.doc("afternoon").update({
"list": alist,
});
return null;
});
部署此功能时出现以下错误:
预期结果:
将所有“状态”字段的值设置为 0。
似乎 alist
是 Firestore 无法处理的对象。要摆脱 Firestore 无法处理的任何部分,您可以执行以下操作:
database.collection("SA1XAoC2A7RYRBeAueuBL92TJEk1")
.doc("afternoon").update({
"list": JSON.parse(JSON.stringify(alist)) //
});
你的 alist
会 return 一个 Promise { <pending> }
。它需要用一个值来实现或用一个原因(错误)拒绝。您应该使用 .then
方法来履行或使用 .catch
方法来获取所有未决承诺的任何错误。请参阅下面的代码以供参考:
const collectionName = "SA1XAoC2A7RYRBeAueuBL92TJEk1";
const documentName = "afternoon";
// created a reference to call between functions
const docRef = database.collection(collectionName).doc(documentName);
// Initialized a new array that will be filled later.
const tasks = [];
// Gets the data from the document reference
docRef.get()
// Fulfills the promise from the `.get` method
.then((doc) => {
// doc.data.list contains the array of your objects. Looping it to construct a `tasks` array.
doc.data().list.forEach((task) => {
// Setting the status to 0 for every object on your list
task.status = 0;
// Push it to the initialized array to use it on your update function.
tasks.push(task);
})
docRef.update({
// The `tasks` structure here must be the same as your Firestore to avoid overwritten contents. This should be done as you're updating a nested field.
list: tasks
}, { merge: true });
})
// Rejects the promise if it returns an error.
.catch((error) => {
console.log("Error getting document:", error);
});
我在代码上留下了一些评论以便更好地理解。
您可能还想查看这些文档:
我正在尝试编写一个预定的云函数来在每天凌晨 12 点重置“状态”的值。这是我的 Firestore 结构:
我以前没有真正尝试过在 javascript 中编码,但这是我用我的一点知识管理的:
const functions = require("firebase-functions");
const admin = require("firebase-admin");
admin.initializeApp();
const database = admin.firestore();
exports.Rst = functions.pubsub.schedule("0 0 * * *").onRun((context) => {
const alist =
database.collection("SA1XAoC2A7RYRBeAueuBL92TJEk1")
.doc("afternoon").get().then((snapshot)=>snapshot.data["list"]);
for (let i=0; i<alist.length; i++) {
alist[i]["status"]=0;
}
database.collection("SA1XAoC2A7RYRBeAueuBL92TJEk1")
.doc("afternoon").update({
"list": alist,
});
return null;
});
部署此功能时出现以下错误:
预期结果:
将所有“状态”字段的值设置为 0。
似乎 alist
是 Firestore 无法处理的对象。要摆脱 Firestore 无法处理的任何部分,您可以执行以下操作:
database.collection("SA1XAoC2A7RYRBeAueuBL92TJEk1")
.doc("afternoon").update({
"list": JSON.parse(JSON.stringify(alist)) //
});
你的 alist
会 return 一个 Promise { <pending> }
。它需要用一个值来实现或用一个原因(错误)拒绝。您应该使用 .then
方法来履行或使用 .catch
方法来获取所有未决承诺的任何错误。请参阅下面的代码以供参考:
const collectionName = "SA1XAoC2A7RYRBeAueuBL92TJEk1";
const documentName = "afternoon";
// created a reference to call between functions
const docRef = database.collection(collectionName).doc(documentName);
// Initialized a new array that will be filled later.
const tasks = [];
// Gets the data from the document reference
docRef.get()
// Fulfills the promise from the `.get` method
.then((doc) => {
// doc.data.list contains the array of your objects. Looping it to construct a `tasks` array.
doc.data().list.forEach((task) => {
// Setting the status to 0 for every object on your list
task.status = 0;
// Push it to the initialized array to use it on your update function.
tasks.push(task);
})
docRef.update({
// The `tasks` structure here must be the same as your Firestore to avoid overwritten contents. This should be done as you're updating a nested field.
list: tasks
}, { merge: true });
})
// Rejects the promise if it returns an error.
.catch((error) => {
console.log("Error getting document:", error);
});
我在代码上留下了一些评论以便更好地理解。
您可能还想查看这些文档: