Select 多个表只有唯一用户并按最新 ID 排序

Question

我有 2 个表，第一个叫做 members:

id  name   show
1   John   1
2   Wil    1
3   George 1
4   Chris  1

第二个叫分数:

id  user_id  score
1   1        90
2   1        70
3   2        55
4   3        30
5   3        40
6   3        100
7   4        30

user_id from score 是成员的id。我想要的是显示一个具有独特 members.id 的得分列表，按 score.score 排序并按最新的 score.id.

排序

我使用以下代码：

SELECT members.id, members.show, score.id, score.user_id, score.score FROM members
INNER JOIN score ON score.user_id = members.id 
WHERE members.show = '1' 
GROUP BY score.user_id
ORDER BY score.score DESC, score.id DESC

输出未按最新的 score.id 排序，但确实仅显示唯一的 user_id：

id  user_id  score
1   1        90
3   2        55
4   3        30
7   4        30

应该是这样的：

id  user_id  score
6   3        100
2   1        70
3   2        55
7   4        30

希望你能帮帮我

Answer 1

您可以使用：

with cte as (
              select id,
                    user_id,
                    score,
                    row_number() over(partition by user_id order by id desc) as row_num
               from score     

) select cte.id,user_id,score
  from cte
  inner join members m on cte.user_id=m.id
  where row_num=1
  order by score desc;

Demo

如果您的 MySQL 服务器不支持 windows 功能，请使用：

select s.id,s.user_id,s.score
from score s
inner join members m on s.user_id=m.id
where s.id in (select max(id) as id 
               from score
               group by user_id
               ) 
               
order by score desc;

Demo

Select 多个表只有唯一用户并按最新 ID 排序

Select multiple tables with only unique users and ordered by latest id

mysql

sql

unique

multiple-tables