Swift 枚举符合单一协议的关联值

Question

如何在不使用详尽开关的情况下将当前枚举案例的关联值作为 Refreshable 获取？ 在这种情况下，我只需要将其作为协议检索，用于每个案例关联类型。

class Type1: Refreshable {}
class Type2: Refreshable {}
class Type3: Refreshable {}

protocol Refreshable {
    func refresh()
}

enum ContentType {
    case content1(Type1 & Refreshable)
    case content2(Type2 & Refreshable)
    case content3(Type3 & Refreshable)
    
    func refreshMe() {
        //self.anyValue.refresh() //Want simple solution to get to the refresh() method not knowing actual current state
    }
}

Answer 1

我已经找到了解决方案，以防有人也需要它。

enum ContentType {
    case content1(Type1 & Refreshable)
    case content2(Type2 & Refreshable)
    case content3(someLabel: Type3 & Refreshable)
    
    func refreshMe() {
        let caseReflection = Mirror(reflecting: self).children.first!.value
        (caseReflection as? Refreshable)?.refresh() //If associated type doesn't have label
        
        let refreshable = Mirror(reflecting: caseReflection).children.first?.value as? Refreshable
        refreshable?.refresh() //If associated type has label
    }
}