减少循环内的行数

Question

我有这个代码：

while count < len(dist_list):
    new.loc[base, "1_dist"],  new.loc[base, "1_t-"]= dist_list[0], new.loc[base, "t-"]
    new.loc[base, "2_dist"],  new.loc[base, "2_t-"]= dist_list[1], new.loc[base, "t-"]
    new.loc[base, "3_dist"],  new.loc[base, "3_t-"]= dist_list[2], new.loc[base, "t-"]
    new.loc[base, "4_dist"],  new.loc[base, "4_t-"]= dist_list[3], new.loc[base, "t-"]
    new.loc[base, "5_dist"],  new.loc[base, "5_t-"]= dist_list[4], new.loc[base, "t-"]
    new.loc[base, "6_dist"],  new.loc[base, "6_t-"]= dist_list[5], new.loc[base, "t-"]
    new.loc[base, "7_dist"],  new.loc[base, "7_t-"]= dist_list[6], new.loc[base, "t-"]
    new.loc[base, "8_dist"],  new.loc[base, "8_t-"]= dist_list[7], new.loc[base, "t-"]
    new.loc[base, "9_dist"],  new.loc[base, "9_t-"]= dist_list[8], new.loc[base, "t-"]
    new.loc[base, "10_dist"],  new.loc[base, "10_t-"]= dist_list[9], new.loc[base, "t-"]
    count += 1

我需要执行相同的代码，但有 100 个变量（1_dist、2_dist...100_dist）。手动地，我将在循环中有 100 行。但我正在寻找一种方法来减少行数。

有人帮我吗？

Answer 1

您已经在迭代 dist_list，因此您不妨使用 enumerate 并使用该索引而不是手动维护 count:

for index, data in enumerate(data_list, 1):
    new.loc[base, f"{index}_dist"], new.loc[base, f"{index}_t-"] = data, new.loc[base, "t-"]

Answer 2

while count < len(dist_list):
new.loc[base, f"{count + 1}_dist"],  new.loc[base, f"{count + 1}_t-"]= dist_list[count], new.loc[base, "t-"]
count += 1

我不太理解代码，但看到你写了这 10 行，你似乎想在第 2 个字符串中再增加 1 个，然后在第 3 个（可能给列表提供索引时）你想要它与计数相同。

减少循环内的行数

Reduce the number of lines inside the loop

python

pandas

while-loop