添加词典到列表。在函数中:$user_list.add("user3", $user_name),我必须输入 "USER3"。如何将变量传递给这个点?
ADD Dictionary to List. In Funtion: $user_list.add("user3", $user_name), I must type in "USER3". How to pass variable to this spot?
$user_list = @{
user1 = [ordered]@{
properties = ("666-555-2345", "1234 E Main St", "Dodge Charger");
misc_data = 34145}
user2 = [ordered]@{
properties = ("666-555-1234", "5678 N Elm St", "Plymouth Dart");
misc_data = 46112}
}
function add_new_user($user_name, $info, $misc){
$user_name = [ordered]@{
properties = $info;
misc_data = $misc}
$user_list.add(**"user3"**, $user_name)
}
add_new_user user3 ("666-555-1357", "9876 S Oak Rd", "Chevy PT Cruiser") 33879
$user_list
注意:这是一个函数,因此为每个新用户实际键入“User#”(在函数内)是不切实际的。
我不知道如何让它为 .ADD 的第一个值获取传递的变量。
$user_list.add("user3", $user_name) =
$user_list.add($user_name, $user_name) =
您可以像这样从您的函数中更新您的 哈希 table:
$user_list = @{
user1 = [ordered]@{
properties = "666-555-2345", "1234 E Main St", "Dodge Charger"
misc_data = 34145
}
user2 = [ordered]@{
properties = "666-555-1234", "5678 N Elm St", "Plymouth Dart"
misc_data = 46112
}
}
function add_new_user($user_name, $info, $misc) {
if($user_list.ContainsKey($user_name)) {
return "$user_name already exists in `$userList"
}
$user_list[$user_name] = [ordered]@{
properties = $info
misc_data = $misc
}
}
我添加了一个条件来检查用户是否已经存在,这样就不会替换 键/值 对,而是 return 用户的消息已经存在。
如果您对其进行测试,您会看到以下内容:
PS /> add_new_user user3 ("666-555-1357", "9876 S Oak Rd", "Chevy PT Cruiser") 33879
PS /> $user_list
Name Value
---- -----
user1 {properties, misc_data}
user3 {properties, misc_data}
user2 {properties, misc_data}
PS /> add_new_user user2 ("666-555-1357", "9876 S Oak Rd", "Chevy PT Cruiser") 33879
user2 already exists in $userList
$user_list = @{
user1 = [ordered]@{
properties = ("666-555-2345", "1234 E Main St", "Dodge Charger");
misc_data = 34145}
user2 = [ordered]@{
properties = ("666-555-1234", "5678 N Elm St", "Plymouth Dart");
misc_data = 46112}
}
function add_new_user($user_name, $info, $misc){
$user_name = [ordered]@{
properties = $info;
misc_data = $misc}
$user_list.add(**"user3"**, $user_name)
}
add_new_user user3 ("666-555-1357", "9876 S Oak Rd", "Chevy PT Cruiser") 33879
$user_list
注意:这是一个函数,因此为每个新用户实际键入“User#”(在函数内)是不切实际的。
我不知道如何让它为 .ADD 的第一个值获取传递的变量。
$user_list.add("user3", $user_name) =
$user_list.add($user_name, $user_name) =
您可以像这样从您的函数中更新您的 哈希 table:
$user_list = @{
user1 = [ordered]@{
properties = "666-555-2345", "1234 E Main St", "Dodge Charger"
misc_data = 34145
}
user2 = [ordered]@{
properties = "666-555-1234", "5678 N Elm St", "Plymouth Dart"
misc_data = 46112
}
}
function add_new_user($user_name, $info, $misc) {
if($user_list.ContainsKey($user_name)) {
return "$user_name already exists in `$userList"
}
$user_list[$user_name] = [ordered]@{
properties = $info
misc_data = $misc
}
}
我添加了一个条件来检查用户是否已经存在,这样就不会替换 键/值 对,而是 return 用户的消息已经存在。
如果您对其进行测试,您会看到以下内容:
PS /> add_new_user user3 ("666-555-1357", "9876 S Oak Rd", "Chevy PT Cruiser") 33879
PS /> $user_list
Name Value
---- -----
user1 {properties, misc_data}
user3 {properties, misc_data}
user2 {properties, misc_data}
PS /> add_new_user user2 ("666-555-1357", "9876 S Oak Rd", "Chevy PT Cruiser") 33879
user2 already exists in $userList