如何遍历 csv 文件行并删除所有多余的空格？

Question

这是我的第一个 python 项目，如果这是一个愚蠢的问题，我深表歉意。我想遍历我创建的一些 csv 文件的行，并用一个 space 替换所有多余的 space，然后用逗号替换那些 space，这样我就可以制作我的专栏.

这是我目前所在的位置：

for new_files in os.walk(target): #"target" is a desktop folder. Only contains .txt and .csv files
for new_name in new_files:
    raw_filename=os.fsdecode(new_name)
    raw_file=target+'\'+new_name
    os.chmod(target,stat.S_IWRITE)
    if new_name.endswith('.csv'):
        for row in csv.reader(open(raw_file)):
            while row.contains('  '):
                str.replace('  ', ' ')
    else:
        continue

我收到以下错误：

filename = fspath(filename)  # Does type-checking of `filename`.
TypeError: expected str, bytes or os.PathLike object, not list

这是我尝试编辑的 csv 文件示例（在原始文件中，每个值之间的间距可变，它们都在 excel 电子表格的 A 列中）：

Ch= a 
[ 1222 20940 85 -49 -11 284 5191 -2] 
Ch= a 
[11772 2319 116 -50 -10 302 5190 -2] 
Ch= a 
[1634 513 187 -49 -10 1051 5190 -2] 
Ch= a 
[ 370 470 1863 -49 -10 11516 5189 -2] 
Ch= a 
[ 294 374 9674 -50 -11 2048 5190 -2] 
Ch= a 
[ 345 490 5238 -50 -10 479 5190 -2]

Answer 1

import os
import re
PATH = "path/to/folder"
for old_files in os.listdir(PATH):
    if old_files.endswith(".csv"):
        with open(f"{PATH}/{old_files}", "r") as f1:
            lines = list(
                map(
                    lambda x: x.strip(),
                    filter(lambda x: "Ch= a" not in x, f1.readlines()),
                )
            )
        with open(f"{PATH}/new_{old_files}", "w") as f2:
            for l in lines:
                m = re.search("(\[\s?)(.*)(\s?\])", l)
                f2.write(m.group(2).replace(" ", ","))
                f2.write("\n")

Answer 2

我假设你正在使用 Python 3，所以我将使用 pathlib 库，它比 os 库更容易使用。

import csv
import pathlib


root = pathlib.Path("~/temp/csv_files").expanduser()
for path in root.glob("*.csv"):

    # Read a text file, convert text lines to row (a list of strings)
    rows = []
    with open(path, "r", encoding="utf-8") as stream:
        for line in stream:
            if line.startswith("Ch="):
                continue
            row = line.replace("[", "").replace("]", "").split()
            rows.append(row)

    # Write the rows
    with open(path, "w", encoding="utf-8") as stream:
        writer = csv.writer(stream)
        writer.writerows(rows)

备注

把root换成你自己的目录
我用.glob()代替os.walk()，比较方便
我假设您想将文本文件就地转换为 CSV，意思是将输出写入同一个文件，替换旧内容

如何遍历 csv 文件行并删除所有多余的空格？

How do I loop through csv file rows and remove all excess spaces?

python

csv

read.csv