遍历多个数组并使用 moment JS 转换值

Question

我有一个函数，它接受一个对象，手动重新排序日期，并将字符串转换为数组

export const convertHoursOfOperation = (service) => {
  const hours = {
    Monday: service.hours_of_operation["monday"],
    Tuesday: service.hours_of_operation["tuesday"],
    Wednesday: service.hours_of_operation["wednesday"],
    Thursday: service.hours_of_operation["thursday"],
    Friday: service.hours_of_operation["friday"],
    Saturday: service.hours_of_operation["saturday"],
    Sunday: service.hours_of_operation["sunday"]
  };

  for (let hour in hours) {
    hours[hour] !== null ? hours[hour] = hours[hour].split(",") : hours[hour] = 'Closed'

    hours[hour] !== 'Closed' ? hours[hour].forEach((h) => moment(h, "HH:mm").format('h:mm')) : null
  }

  return hours;
}

来自hours[hour] !== null ? hours[hour] = hours[hour].split(",") : hours[hour] = 'Closed'

的输出

monday: '09:00, 15:00' => monday: [09:00, 15:00] 或 monday: null => monday: 'Closed'

然后我尝试遍历数组（如果它是一个数组）并使用 moment.

将值从军用时间转换为标准时间

所以现在我想要的输出应该是：

monday: [09:00, 15:00] => monday: [9:00, 3:00]

目前 hours[hour] !== 'Closed' ? hours[hour].forEach((h) => moment(h, "HH:mm").format('h:mm')) : null 行没有转换任何东西。我在这里做错了什么？

Answer 1

您没有将 moment() 设置为任何内容。设置该特定索引处的值。正确的代码应该是这样的：

hours[hour] !== 'Closed' ? hours[hour].forEach((h,index) => hours[hour][index] = moment(h, "HH:mm").format('h:mm')) : null;

遍历多个数组并使用 moment JS 转换值

Looping through multiple arrays and converting values using moment JS

javascript

momentjs