是否有实用程序类型或类似的东西从另一个派生密钥的名称？

Question

希望不大，但我希望能够从现有界面生成一个新界面，但键名是为原始界面派生的。

下面是我希望能够做的事情的示例：

鉴于此源对象：

interface Car {
  brand: Brand;
  model: string;
  year: number;
}

我希望能够声明一个接口：

interface CarSetters {
  setBrand: (brand: Brand) => any;
  setModel: (model: string) => any;
  setYear: (year: number) => any;
}

但我不想像上面那样手动声明它。相反，我希望能够像这样使用它：

type CarSetters = Setters<Car>

或

type CarState = Car & Setters<Car>

Answer 1

看起来是一个非常简单的映射：

type Brand = boolean;
interface Car {
  brand: Brand;
  model: string;
  year: number;
};
type CarSetters = {
    [T in keyof Car as `set${Capitalize<T>}`]: (newValue: Car[T]) => any;
};

为了防止符号引起问题，您可以这样做：

type CarSetters = {
    [T in keyof Car as T extends symbol ? never : `set${Capitalize<T>}`]: (newValue: Car[T]) => any;
};

或

type CarSetters = {
    [T in keyof Car as T extends symbol ? never : `set${Capitalize<T>}`]: (newValue: Car[T]) => any;
} & {
    [T in keyof Car as T extends symbol ? T : never]: Car[T];
};

Answer 2

我能够设计出一个完全符合我要求的泛型，这主要归功于，我已经接受了它，因为它确实回答了我提出的问题。但我也分享了我想出的泛型：

type Setters<T> = {
  [K in keyof T as K extends string ? `set${Capitalize<K>}` : never]: (
    value: T[K]
  ) => any;
};

type State<T> = T & Setters<T>

是否有实用程序类型或类似的东西从另一个派生密钥的名称？

Is there a utility type or something similar derive the name of a key from another?

typescript

generics

typescript-generics

derived-types