颤动无法识别列表视图构建器中的列表属性

Question

我想列出一些不同的烤肉店。我创建了一个列表，其中包含我需要的所有属性，但 flutter 无法识别或显示属性“name”或 Listview 构建器中的任何其他属性，

我不明白为什么我很欣赏每一个有用的命令。

错误：

The getter 'image' isn't defined for the type 'List Doener'.

并且此 Doenerscrollliste class 在 body 容器内。

class DoenerScrollListe extends StatefulWidget {
  const DoenerScrollListe({Key? key}) : super(key: key);

  @override
  State<DoenerScrollListe> createState() => _DoenerScrollListeState();
}

class _DoenerScrollListeState extends State<DoenerScrollListe> {
  late PageController _pageController;
  int initialPage = 1;

  @override
  void initState() {
    super.initState();
    _pageController = PageController();
  }

  @override
  void dispose() {
    super.dispose();
    _pageController.dispose();
  }

  @override
  Widget build(BuildContext context) {
    return ListView.builder(
      itemCount: Doener_all.length,
      scrollDirection: Axis.vertical,
      addAutomaticKeepAlives: false,
      shrinkWrap: true,
      itemBuilder: (context, index) => Container(
        height: 120,
        width: double.infinity,
        margin: const EdgeInsets.all(10),
        decoration: BoxDecoration(
            borderRadius: BorderRadius.circular(20),
            color: Colors.orange[400],
            image: DecorationImage(image: AssetImage(Doener_all.image))),
      ),
    );
  }
}

和我的模型文件

import 'package:flutter/material.dart';
class Doener {
  final String name;
  final String image;
  final String ratingImage;
  final String price;
  final String describtion;

  Doener({
    required this.name,
    required this.image,
    required this.ratingImage,
    required this.price,
    required this.describtion,
  });
}

// ignore: non_constant_identifier_names
List<Doener> Doener_all = [
  Doener(
      name: "Rüyam",
      image: "assets/images/Ryam.jpg",
      ratingImage: "dsd",
      price: "4,10",
      describtion: "Sehr guter Döner Top Preis Leistung"),
  Doener(
    name: "Pamfeliya",
    image: "assets/images/Pamfilya.jpg",
    ratingImage: "asdaa",
    price: "4,10",
    describtion: "Bestes Fleisch",
  ),
  Doener(
      name: "K'Ups",
      image: "assets/images/KUps.jpg",
      ratingImage: "sdsd",
      price: "4,10",
      describtion: "Guter Döner"),
];

Answer 1

你想在这种情况下获得特定图像，替换

AssetImage(Doener_all.image)

与

AssetImage(Doener_all[index].image))

更多关于 List。

颤动无法识别列表视图构建器中的列表属性

flutter can't recognize list atributes in listview builder

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builder

flutter