我正在尝试在 sql.js 中创建两个表，但存在关于外键约束的错误。创建第一个没有问题table

Question

示例代码

<script>
config = {
    locateFile: filename => `sql-wasm.wasm`
  }
initSqlJs(config).then(function(SQL)
{
    //Create the database
    const db = new SQL.Database();

    //create first table - Questions (Parent Table)
    let question = "CREATE TABLE Questions(qid INT NOT NULL, qdesc CHAR, PRIMARY KEY(qid));\
        INSERT INTO Questions VALUES(1, 'set1');\
        INSERT INTO Questions VALUES(2, 'set2');\
        INSERT INTO Questions VALUES(3, 'set3');\
        INSERT INTO Questions VALUES(4, 'set4');\
        INSERT INTO Questions VALUES(5, 'set5');";
    db.run(question);
    const result = db.exec("SELECT * FROM Questions");
    console.log(result);
    
    //create second Table - Qimages (Child Table)
    let qimage = "CREATE TABLE Qimages(img_id INT AUTO_INCREMENT, imgurl VARCHAR,FOREIGN KEY (qid) REFERENCES Questions(qid));\
        INSERT INTO Qimages VALUES('https://www.w3schools.com/howto/img_woods.jpg',1);\
        INSERT INTO Qimages VALUES('https://www.w3schools.com/howto/img_5terre.jpg',1);\
        INSERT INTO Qimages VALUES('https://www.w3schools.com/howto/img_mountains.jpg',2);";
    db.run(qimage);
    const res = db.exec("SELECT * FROM Qimages");
    console.log(res);
</script>

下面是我遇到的错误

uncaught (in promise) Error: unknown column "qid" in foreign key definition

Answer 1

正如消息所说，Qimages 中没有 qid 列 table。我怀疑你想要：-

CREATE TABLE Qimages(img_id INT AUTO_INCREMENT, imgurl VARCHAR,qid INTEGER REFERENCES Questions(qid));

因此，使用外键约束声明的列级版本的 qid 列（现在已定义）的值必须在问题 table 的 qid 列中具有相应的值。

或者你可以使用：-

CREATE TABLE Qimages(img_id INT AUTO_INCREMENT, imgurl VARCHAR,qid INTEGER, FOREIGN KEY (qid) REFERENCES Questions(qid));

我正在尝试在 sql.js 中创建两个表，但存在关于外键约束的错误。创建第一个没有问题table

I'm trying to create Two Tables in sql.js but there is an error regarding foreign key constraint. there is no problem in creating the first table

javascript

sqlite

sql.js