按一定数量拆分字符串并将结果保存为 python 中的列表

Question

所以我有一个字符串 (string = "Cipher Programming - 101!")，我想将它分成六个字符（包括空格和特殊符号）并将结果存储为 Python.

中的列表

预期输出：['Cipher'、“Progr”、'amming'、“- 101”、“!”]

Answer 1

只需一个普通的 for 循环就可以解决问题：

string = "Cipher Programming - 101!"
n = 6
[line[i:i+n] for i in range(0, len(string), n)]

Answer 2

上面的答案非常有效 - 非常紧凑和优雅，但为了更好地理解它，我决定包含一个带有常规 for-loop.

的答案

string = "Cipher Programming - 101!"  # can be any string (almost)

result = []
buff = ""
split_by = 6  # word length for each string inside of 'result'

for index, letter in enumerate(string):
    buff += letter

    # first append and then reset the buffer
    if (index + 1) % split_by == 0:
        result.append(buff)
        buff = ""

    # append the buffer containing the remaining letters
    elif len(string) - (index + 1) == 0:
        result.append(buff)

print(result) # output: ['Cipher', ' Progr', 'amming', ' - 101', '!']

按一定数量拆分字符串并将结果保存为 python 中的列表

split string by certain number and save the result as a list in python

python

string

split

list

python-3.x