class 属性 在 c# 中解析 json 数据时的操作
class property manipulation when parsing json data in c#
我正在练习网络 api。我的目标是创建一个 Get 端点,它从外部 api 接收数据,然后 return 一个不同的结果。外部 api link: https://www.themealdb.com/api/json/v1/1/search.php?f=a,外部 api 数据如下所示:
{
"meals": [
{
"idMeal": "52768",
"strMeal": "Apple Frangipan Tart",
"strDrinkAlternate": null,
"strCategory": "Dessert",
.....
},
{
"idMeal": "52893",
"strMeal": "Apple & Blackberry Crumble",
....
}
]
}
我希望我的端点提供不同的结果,如下所示:
[
{
"idMeal": "52768",
"strMeal": "Apple Frangipan Tart",
"ingredients": ["Apple", "sugar"...]
},
{
"idMeal": "52893",
"strMeal": "Apple & Blackberry Crumble",
"ingredients": ["Apple", "sugar"...]
}
]
下面的代码是我到目前为止尝试的代码,它正在工作,但是当我将 属性 成分 1 从 public 更改为私有时,列表中的成分将变为空,还有,配料那么多,有的默认是null,如果是null我就不想加了,请问这两个问题怎么解决?非常感谢
using System.Text.Json;
using System.Text.Json.Serialization;
using Microsoft.AspNetCore.Mvc;
using RestSharp;
namespace testAPI.Controllers;
public class Content
{
[JsonPropertyName("meals")]
public List<Meal> Meals { get; set; }
}
public class Meal
{
[JsonPropertyName("idMeal")]
public string MealId { get; set; }
[JsonPropertyName("strMeal")]
public string Name { get; set; }
[JsonPropertyName("strIngredient1")]
public string Ingredient1 { get; set; }
[JsonPropertyName("strIngredient2")]
public string Ingredient2 { get; set; }
[JsonPropertyName("strIngredient20")]
public string Ingredient20 { get; set; }
public List<string> Ingredients
{
get { return new List<string>(){Ingredient1, Ingredient2, Ingredient20};}
}
}
[ApiController]
[Route("api/[controller]")]
public class DishesController : ControllerBase
{
[HttpGet]
public async Task<IActionResult> GetAllRecipes()
{
var client = new RestClient($"https://www.themealdb.com/api/json/v1/1/search.php?s=");
var request = new RestRequest();
var response = await client.ExecuteAsync(request);
var mealList = JsonSerializer.Deserialize<Content>(response.Content);
return Ok(mealList.Meals);
}
}
一次解决一个问题...
the moment I changed property ingredient1 from public to private, that ingredient in list will become null
更改访问修饰符会同时影响反序列化和序列化,因此这不能仅用于阻止它序列化 属性。您应该将数据模型拆分为您想要接收的内容和您想要接收的内容 expose/return.
there are so many ingredients, some of them are null by default, I don't want to add them if they are null
除了拆分数据模型之外,您还可以在从一个模型映射到另一个模型时处理此问题。
以下代码应该可以解决这两个问题:
namespace TheMealDb.Models
{
// These are the models you receive from TheMealDb
// JSON converted to classes with https://json2csharp.com/
public class Root
{
public List<Meal> meals { get; set; }
}
public class Meal
{
public string idMeal { get; set; }
public string strMeal { get; set; }
public string strIngredient1 { get; set; }
public string strIngredient2 { get; set; }
public string strIngredient3 { get; set; }
// Other properties removed for brevity...
}
}
namespace Internal.Models
{
// This is the model you want to return from your controller action
public class Meal
{
[JsonPropertyName("id")] // No need to use the same name as from themealdb
public string Id { get; set; }
[JsonPropertyName("name")]
public string Name { get; set; }
[JsonPropertyName("ingredients")]
public List<string> Ingredients { get; set; }
}
}
现在,要获取、映射和 return 控制器操作中的数据:
[HttpGet]
public async Task<IActionResult> GetAllRecipes()
{
var client = new RestClient($"https://www.themealdb.com/api/json/v1/1/search.php?s=");
var request = new RestRequest();
var response = await client.ExecuteAsync(request);
// Deserialize to the "TheMealDb" models
var mealList = JsonSerializer.Deserialize<TheMealDb.Models.Root>(response.Content);
// Map to your own models
var myMealList = mealDbList.meals?.Select(MapToInternal);
return Ok(myMealList);
}
// Map "TheMealDb" model to your own model
private Internal.Models.Meal MapToInternal(TheMealDb.Models.Meal externalMeal)
{
return new Internal.Models.Meal
{
Id = externalMeal.idMeal,
Name = externalMeal.strMeal,
Ingredients = new []
{
externalMeal.strIngredient1,
externalMeal.strIngredient2,
externalMeal.strIngredient3,
// ...
}
// Remove empty/null ingredients
.Where(ingr => !string.IsNullOrEmpty(ingr))
.ToList()
};
}
我正在练习网络 api。我的目标是创建一个 Get 端点,它从外部 api 接收数据,然后 return 一个不同的结果。外部 api link: https://www.themealdb.com/api/json/v1/1/search.php?f=a,外部 api 数据如下所示:
{
"meals": [
{
"idMeal": "52768",
"strMeal": "Apple Frangipan Tart",
"strDrinkAlternate": null,
"strCategory": "Dessert",
.....
},
{
"idMeal": "52893",
"strMeal": "Apple & Blackberry Crumble",
....
}
]
}
我希望我的端点提供不同的结果,如下所示:
[
{
"idMeal": "52768",
"strMeal": "Apple Frangipan Tart",
"ingredients": ["Apple", "sugar"...]
},
{
"idMeal": "52893",
"strMeal": "Apple & Blackberry Crumble",
"ingredients": ["Apple", "sugar"...]
}
]
下面的代码是我到目前为止尝试的代码,它正在工作,但是当我将 属性 成分 1 从 public 更改为私有时,列表中的成分将变为空,还有,配料那么多,有的默认是null,如果是null我就不想加了,请问这两个问题怎么解决?非常感谢
using System.Text.Json;
using System.Text.Json.Serialization;
using Microsoft.AspNetCore.Mvc;
using RestSharp;
namespace testAPI.Controllers;
public class Content
{
[JsonPropertyName("meals")]
public List<Meal> Meals { get; set; }
}
public class Meal
{
[JsonPropertyName("idMeal")]
public string MealId { get; set; }
[JsonPropertyName("strMeal")]
public string Name { get; set; }
[JsonPropertyName("strIngredient1")]
public string Ingredient1 { get; set; }
[JsonPropertyName("strIngredient2")]
public string Ingredient2 { get; set; }
[JsonPropertyName("strIngredient20")]
public string Ingredient20 { get; set; }
public List<string> Ingredients
{
get { return new List<string>(){Ingredient1, Ingredient2, Ingredient20};}
}
}
[ApiController]
[Route("api/[controller]")]
public class DishesController : ControllerBase
{
[HttpGet]
public async Task<IActionResult> GetAllRecipes()
{
var client = new RestClient($"https://www.themealdb.com/api/json/v1/1/search.php?s=");
var request = new RestRequest();
var response = await client.ExecuteAsync(request);
var mealList = JsonSerializer.Deserialize<Content>(response.Content);
return Ok(mealList.Meals);
}
}
一次解决一个问题...
the moment I changed property ingredient1 from public to private, that ingredient in list will become null
更改访问修饰符会同时影响反序列化和序列化,因此这不能仅用于阻止它序列化 属性。您应该将数据模型拆分为您想要接收的内容和您想要接收的内容 expose/return.
there are so many ingredients, some of them are null by default, I don't want to add them if they are null
除了拆分数据模型之外,您还可以在从一个模型映射到另一个模型时处理此问题。
以下代码应该可以解决这两个问题:
namespace TheMealDb.Models
{
// These are the models you receive from TheMealDb
// JSON converted to classes with https://json2csharp.com/
public class Root
{
public List<Meal> meals { get; set; }
}
public class Meal
{
public string idMeal { get; set; }
public string strMeal { get; set; }
public string strIngredient1 { get; set; }
public string strIngredient2 { get; set; }
public string strIngredient3 { get; set; }
// Other properties removed for brevity...
}
}
namespace Internal.Models
{
// This is the model you want to return from your controller action
public class Meal
{
[JsonPropertyName("id")] // No need to use the same name as from themealdb
public string Id { get; set; }
[JsonPropertyName("name")]
public string Name { get; set; }
[JsonPropertyName("ingredients")]
public List<string> Ingredients { get; set; }
}
}
现在,要获取、映射和 return 控制器操作中的数据:
[HttpGet]
public async Task<IActionResult> GetAllRecipes()
{
var client = new RestClient($"https://www.themealdb.com/api/json/v1/1/search.php?s=");
var request = new RestRequest();
var response = await client.ExecuteAsync(request);
// Deserialize to the "TheMealDb" models
var mealList = JsonSerializer.Deserialize<TheMealDb.Models.Root>(response.Content);
// Map to your own models
var myMealList = mealDbList.meals?.Select(MapToInternal);
return Ok(myMealList);
}
// Map "TheMealDb" model to your own model
private Internal.Models.Meal MapToInternal(TheMealDb.Models.Meal externalMeal)
{
return new Internal.Models.Meal
{
Id = externalMeal.idMeal,
Name = externalMeal.strMeal,
Ingredients = new []
{
externalMeal.strIngredient1,
externalMeal.strIngredient2,
externalMeal.strIngredient3,
// ...
}
// Remove empty/null ingredients
.Where(ingr => !string.IsNullOrEmpty(ingr))
.ToList()
};
}