一对多单向关联插入查询失败

Question

我有 User 和 Address 具有 one-to-many 单向关系的实体。当我尝试插入带有 Address 详细信息的 User 时，它因异常 "Referential integrity constraint violation" 而失败，因为我检查了 Address没有插入 userId 它有 0 我不明白这有什么问题。

我的用户实体：

        @Entity 
        @Table(name = "users")
        public class User{
        
            @Id
            @GeneratedValue(strategy = GenerationType.IDENTITY)
            @Column(name = "ID")
            private long id;
            
            @OneToMany(orphanRemoval = true,cascade = CascadeType.ALL, fetch=FetchType.EAGER)
            @JoinColumn(name = "USER_ID", referencedColumnName = "ID")
            private List<Address> address;
    // other table columns
        
         }

我的地址实体：

    @Entity
    @Table(name = "address")
    public class Address{
        
        @Id
        @GeneratedValue(strategy = GenerationType.IDENTITY)
        @Column(name = "ID")
        private long id;
        
        @Column(name = "USER_ID")
        private long userId;
    //other table columns
    }

我的控制器：

    @PostMapping("/")
    public ResponseEntity<UserDTO> saveUser(@RequestBody UserRequestDTO userRequestDTO){
            try {
                if (userRequestDTO != null) {
                    return new ResponseEntity<>(userService.saveUser(userRequestDTO), HttpStatus.CREATED);
                }
            } catch (Exception ex) {
                return new ResponseEntity<>(HttpStatus.INTERNAL_SERVER_ERROR);
            }
            return null;
        }

我的服务层：

    @Override
        public UserDTO saveUser(UserRequestDTO userDto) {
            User obj = modelMapper.map(userDto, User.class);
            System.out.println(obj.toString());
            obj = userRepository.save(obj);
            return modelMapper.map(obj, UserDTO.class);
        }

这是我的 UserRequestDTO 我有所有属性

    public class UserRequestDTO {
    
        private long id;
        private long clientId;
        private String clientName;
        private String email;
        private String firstName;
        private String lastName;
        private String employeeNo;
        private String designation; 
        private String status;
        private String phoneNumber;
        private String employeeType;
        private String reportingTo;
        private String department;
        private String division;
        private String password;
        private String gender;  
        private String bloodGroup;
        private String maritalStatus;
        private String spouseName;
        private String noOfChildren;
        private Date dateOfBirth;
        private Date hiredDate;
        private LocalDate createdDate;
        private String createdBy;
        private LocalDate updatedDate;
        private String updatedBy;
        private List<Address> address;
    }

查了很多在线教程，但无法找到根本原因来自控制台的错误消息：

    User(id=0, clientId=1, email=user@gmail.com, firstName=user 10, lastName=K, password=password@123, employeeNo=EH5213, phoneNumber=9999999990, status=A, designation=Developer, employeeType=FullTime, reportingTo=Roshan, department=Information Technology, division=division, locationId=null, gender=null, bloodGroup=null, maritalStatus=null, spouseName=null, noOfChildren=null, dateOfBirth=null, hiredDate=null, createdDate=2022-03-25, createdBy=admin, updatedDate=2022-03-25, updatedBy=admin, organization=null, address=[Address(id=0, clientId=1, userId=0, address1=add1Sample, address2=add2Sample, state=sample, addressType=P, country=sample, city=sample, zipCode=000002, primaryPhone=1111111111, secondaryPhone=2222222222, active=true, createdDate=2022-03-25, createdBy=admin, updatedDate=2022-03-25, updatedBy=admin), Address(id=0, clientId=1, userId=0, address1=sample2, address2=add2sample2 , state=sample2, addressType=T, country=sample2, city=sample2, zipCode=000008, primaryPhone=4444444444, secondaryPhone=666666666, active=true, createdDate=2022-03-25, createdBy=admin, updatedDate=2022-03-25, updatedBy=admin)], employeeGroups=null)
    Hibernate: insert into users (id, blood_group, client_id, created_by, created_date, date_of_birth, department, designation, division, email, employee_no, employee_type, first_name, gender, hired_date, last_name, location_id, marital_status, no_of_children, organization_id, password, phone_number, reporting_to, spouse_name, status, updated_by, updated_date) values (default, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?)
    Hibernate: insert into address (id, active, address_line_1, address_line_2, address_type, city, client_id, country, created_by, created_date, primary_phone, secondary_phone, state, updated_by, updated_date, user_id, zip_code) values (default, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?)
    [2m2022-03-30 12:41:25.689[0;39m [33m WARN[0;39m [35m13308[0;39m [2m---[0;39m [2m[nio-8085-exec-2][0;39m [36mo.h.engine.jdbc.spi.SqlExceptionHelper  [0;39m [2m:[0;39m SQL Error: 23506, SQLState: 23506
    [2m2022-03-30 12:41:25.702[0;39m [31mERROR[0;39m [35m13308[0;39m [2m---[0;39m [2m[nio-8085-exec-2][0;39m [36mo.h.engine.jdbc.spi.SqlExceptionHelper  [0;39m [2m:[0;39m Referential integrity constraint violation: "FK6I66IJB8TWGCQTETL8EEEED6V: PUBLIC.ADDRESS FOREIGN KEY(USER_ID) REFERENCES PUBLIC.USERS(ID) (0)"; SQL statement:
    insert into address (id, active, address_line_1, address_line_2, address_type, city, client_id, country, created_by, created_date, primary_phone, secondary_phone, state, updated_by, updated_date, user_id, zip_code) values (default, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?) [23506-200]

Answer 1

这可以通过在实体级别进行一些小的更改来解决：
变化一：在您的用户实体中添加 nullable=false，如下所示：

@Entity 
@Table(name = "users")`
public class User{`
    
    @Id
    @GeneratedValue(strategy = GenerationType.IDENTITY)
    @Column(name = "ID")
    private long id;
        
    @OneToMany(orphanRemoval = true,cascade = CascadeType.ALL, fetch=FetchType.EAGER)
    @JoinColumn(name = "USER_ID", referencedColumnName = "ID", nullable = false)
     private List<Address> address;
// other table columns
}

变2：在您的 Address 实体中添加 insertable = false 和 updatable = false，像这样

@Entity
@Table(name = "address")
public class Address{
    
    @Id
    @GeneratedValue(strategy = GenerationType.IDENTITY)
    @Column(name = "ID")
    private long id;

    @Column(name = "USER_ID", insertable = false, updatable = false)
    private long userId;
//other table columns
}

使用 nullable=false : 它将非空约束应用于特定的数据库列

要了解 insertable = false, updatable = false 的用法请参考这个 :Please explain about insertable=false and updatable=false in reference to the JPA @Column annotation

Answer 2

您必须先插入 User 然后再插入 Address 意味着您必须在插入 Address 之前获取 User 的引用。但是在 Unidirectional Mapping 中，您不需要为插入 Address 添加代码，因为它会自动从 User 获取引用。 DTO 这里不需要。

从 Address.java 中删除此列，因为手动插入外键是不好的做法：

@Column(name = "USER_ID", insertable = false, updatable = false)
private long userId;

下面是修改后的代码：

控制器

@RequestMapping(value = "/")
@ResponseBody
public ResponseEntity<User> addUser(@RequestBody User user)
{
    userRepository.save(user);
    return new ResponseEntity<>(user, HttpStatus.CREATED);
}

你不想在这里创建 DTO...

一对多单向关联插入查询失败

One To Many Unidirectional association insert query getting failed

java

hibernate

h2

spring-boot